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3 years ago

3. A computer is worth $4000 when it is new. After each year it is worth half what it was the previous year

Mathematics

2 answers:

MrMuchimi3 years ago

7 0

Answer:

Answer is 500

btw did round sorry

Step-by-step explanation:

First year

4,000 divided by 2,000=2,000

Second year

2,000 divided by 2=1,000

Third year

1,000 divided by 2=500

Helga [31]3 years ago

4 0

*I know it's already been answered, but I just wanted to add a different version of the steps. While this particular question could be answered in like 3 seconds, this method is a lot quicker when they want you to find 30th term lol

Answer:

500

Step-by-step explanation:

First, set up your equation:

an = a1 * r ^ (n-1)

a1 is 2000, because it is the first term (4000 is the 0th term).

4000*(1/2)=2000.

an = 2000 * (1/2) ^ (n-1)

Now, subsitute n for 3:

a3 = 2000 * (1/2) ^ (3-1)

Solve:

a3 = 2000 * (1/2) ^ 2

a3 = 2000 * 0.25

a3 = 500

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Priya drew a circle whose area is 25 cm. Dan drew a circle whose diameter is 4 times the radius of Priya's circle. How many time

Vitek1552 [10]

Answer:

400

Step-by-step explanation:

first work out the radius of priya's circle with the equation a = $\pi r^{2}$

$25 = \pi r^{2}$

$\frac{25}{\pi } = r^{2}$

$r = \sqrt{\frac{25}{\pi } }$

we know the diameter of a circle is 2 times the radius so the diameter of priya's circle is 2x $\sqrt{\frac{25}{\pi } }$

this means that if the diameter of dan's circle is 4 times bigger it must be

8x $\sqrt{\frac{25}{\pi } }$

to find the radius of dan's circle we divide the diameter by to 2 to give

4x $\sqrt{\frac{25}{\pi } }$

then use the a= $\pi r^{2}$ equation again

$a= (4 \sqrt{\frac{25}{\pi } })^{2} \pi$

which equals 400

hope that helped

6 0

3 years ago

Given each of the following areas, what would be the radius of each circle? a. A = 530.66 m2 b. A = 907.46 sq. ft. c. A = 379.94

ra1l [238]

Area for a circle is $A= \pi r^2$ . We will fill in each area and then solve for the radius. $530.66m^2= \pi r^2$ and $\frac{530.66m^2}{3.14}=r^2$ . ∴ $169=r^2$ and r = 13. For b, $907.46ft^2= \pi r^2$ and $\frac{907.46ft^2}{3.14}=r^2$ . $289=r^2$ , ∴ r = 17. For c, $379.94mi^2= \pi r^2$ , and $\frac{379.94mi^2}{3.14}=r^2$ . ∴, $121=r^2$ and r = 11. For d, $1962.5cm^2= \pi r^2$ , and $\frac{1962.5cm^2}{3.14}=r^2$ . ∴, $625=r^2$ so r = 25. And there you have it!

3 0

3 years ago

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mestny [16]

Answer:

Step-by-step explanation:

Complex roots of quadratic functions occur when the discriminant is negative.

Discriminant

$b^2-4ac\quad\textsf{when}\:\:ax^2+bx+c=0$