We will use Binomial Distribution in this case.
Since the coin is tossed 15 times. N which is the number of trails will be 15.
P = Probability of heads
Q = Probability of tails
X = No. heads occurring in each toss.
So, now we have to find the probability for exactly 10 heads.
P(x = 10) = C(15, 10) P^x Q^N-x
C(15, 10) (1/2)^10 (1/2)^5 = 0.0916
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Related Questions (More Answers Below)
Eliminate p terms
times 2nd equation by -1
q-2p=-5
add to 2nd equation
q-2p=-5
<u>7q+2p=29 +</u>
8q+0p=24
8q=24
divide both sides by 8
q=3
sub back
2p-q=5
2p-3=5
add 3
2p=8
divide by 2
p=4
p=4
q=3
If M is the midpoint of segment RS, then
M = (R + S)/2
2M = R + S . . . . . multiply by 2
S = 2M - R = 2(8, -2) -(10, 5) = (6, -9) . . . . put in the given values
Jasmine would need $17 .
Because 4 green bags times 18 dollars is 72 + 3 purple bags times 15 dollars is 45,so 72+45= 117
So, Jasmine will need 17dollars
Answer:
1) biased sample
2) random sampling
Step-by-step explanation:
Since the results are based on feedback of students in only one class, it's not a good representative of the entire student body.
Also, since it's a math class there will be a bias.
Better method would be randomly selecting students from the entire school students list and take their feedback
