Answer:
Mass of Jupiter = 4.173×10^15kg
Explanation:
Using Kepler's 3rd law, it states that the orbital period T is related to the distance,r as:
T^2 = GM/4 pi × r^3
Where G = universal gravitational constant
r = radius
M = masd of jupiter
Rearranging the formular to make M the subject of formular
T^2 × 4 pi = G M × r^3
(T^2 × 4 pi) / (G× r^3) = M
(1.24^2 × 4 × 3.142) /(6.672×10^-11)(4.11×10^8)^3
M = 19.32 /6.672×10^-11)(4.11×10^8)^3
M = 19.32 / 4.63 ×10^15
M = 4.173×10^15kg
The height of the bag pack is 0.7 m.
The gravitational potential energy is given by the formula
P=mgh
Now plugging the values in the above equation to calculate the height of the bag pack
54.9=8*9.81*h
h=0.7 m
Therefore the bag pack is lifted to the height of 0.7 m.
Answer:
0.7 secs
Explanation:
In this question, the speed does not change as the mass changes. So we can use
Δ<em>t=Δ∨x/χgμ............................equ 1</em>
To stop, the final speed will be 0
Therefore,
<em>Δvx=vf-vt</em>
Δvx=0-4m/s
= -4m/s
Now substitute the various values in equ 1
Δ<em>t=Δ∨x/χgμ</em>
Δ<em>t= -</em>4m/s/(9.8m/s∧2) (0.6)
Δ<em>t=</em>0.7 secs
The answer would have to be 8.47 m/s/s because the backwards pull + the rate of speed it is going would have to be added to get the answer to compensate for the backwards pull
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I hope this helps;)