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Ilia_Sergeevich [38]
3 years ago
7

How did the light dress up for the costume party answeres

Mathematics
1 answer:
SOVA2 [1]3 years ago
8 0

The light dress up for the costume party can be as feather Hope i helped

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joe drove 408 miles using 16 gallons of gas at this ratr how many mokrs would he drive using 11 gallons of gas
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I was on the right track, lol. 280.5 miles.
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Kim has 68 spoons, there are 8 boxes of spoons, how many spoons go into each box?
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8 in each of the first four boxes and 9 in each of the second four boxes
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PLEASE HELP ASAP! WILL GIVE BRAINLIEST! ^^ Sarah and Noah work at read on bookstore and get paid the same hourly wage. The table
Inessa05 [86]

Answer:

1) 8= (5xW)+(3xW) (she worked 8 hours total over spread of two days)

2) 8=8xW (he worked 8 hours total over one day)

3) Yes, they worked the same number of hours, they just worked for an different amount of hours.

Step-by-step explanation:

I kind of explained it in the answer, but if you'd like a clarification.

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Each pound of fruit costs $4. Write an expression that shows the total cost of fruit use the variable you identified in the ques
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This is my last question can someone help me with my homework.
shutvik [7]

9514 1404 393

Answer:

  C, A, A

Step-by-step explanation:

In general, you ...

  • identify the coefficients of one of the variables
  • swap them, and negate one of them
  • multiply the corresponding equations by the "adjusted" coefficients.

__

In problem 1, the x-coefficients are 8 and 2. A common factor of 2 can be removed so that we're dealing with the numbers 4 and 1. Assuming we want to multiply one of the equations by 1, leaving it unchanged, the value we want to multiply by will be -4. After we swap the coefficients, that multiplier is associated with equation 2:

  multiply equation 2 by -4 . . . (eliminates x)

Likewise, the y-coefficients in problem 1 are -1 and 3. Again, if we want to multiply one of the equations by 1, leaving it unchanged, the coefficient we will change the sign of is -1 (becomes 1). After we swap the coefficients, the multiplier 3 is associated with equation 1:

  multiply equation 1 by 3 . . . (eliminates y)

These two choices are B and A, respectively, so the one that does NOT work for problem 1 is choice C, as indicated below.

__

The other problems are worked in a similar fashion.

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