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sladkih [1.3K]
2 years ago
8

Relationship between genes chromosomes an dna .

Chemistry
2 answers:
omeli [17]2 years ago
8 0

Answer:

Genes are segments of DNA that contain the code for a paticular  protein that works in one or more types of cells in the body. Chromosomes are structures within cells that contain a person's genes. Genes are contained in chromosomes, which are in the cell nucleus.

Explanation:

Andrej [43]2 years ago
5 0

Answer:

The answer should be A

Explanation:

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How many kg of carbon dioxide are used per year to produce their arm and hammer baking soda?
cestrela7 [59]
The complete question would be as follows:

700,000 tons of baking soda are produced per year. <span>How many kilograms of carbon dioxide are used per year to produce baking soda?

We calculate as follows:

</span><span>CO2(g) + NH3(aq) + NaCl(aq) + H2O -----> NaHCO3(s) + NH4Cl(aq)
</span>
700000 tons NaHCO3 ( 907.185 kg / 1 ton ) (<span>1 kmole NaHCO3 / 84.0 kg NaHCO3) x (1 kmole CO2 / 1 kmole NaHCO3) x (44.0 kg CO2 / 1 kmole) = 3x10^8 kg CO2

Hope this answers the question. Have a nice day.</span>
3 0
3 years ago
I NEED HELP FAST, BRAINLIEST! :)
castortr0y [4]

Answer:

decrease is the answer i think

Explanation:

5 0
3 years ago
If the products in a chemical equation include h2o, what specific type of reaction is occuring? Is a polymer being made or broke
anzhelika [568]

There are two kinds of polymers : addition polymers and condensation polymers

In case of addition polymers, there is simple addition of unsaturated monomeric units. example: polythene

While in case of condensation polymers, the monomers combine with the elimination of a small molecule like H2O, HCl, NH3 etc.

So here as there is formation of H2O as product there is formation of a polymer and that too a condensation polymer

Example: condensation polymer of diamine and dicarboxylic acid to form a polyamide (Nylon-6,6)

Answer: condensation

formation of polymer

7 0
3 years ago
Draw the structure of the starting material in the ozonolysis reaction below. Hint: The starting material and product have the s
Crank
<h3>Answer:</h3>

            The starting material involved in the formation of 5-Oxoheptanal is 1-ethylcyclopent-1-ene as shown in reaction below.

<h3>Explanation:</h3>

                       Ozone is one of the reactive allotrope of oxygen. It reacts vigorously with unsaturated compounds like alkenes and alkynes. In this reaction alkene and O₃ first react to produce Molozonide which is highly unstable and rearranges to form a stable ozonide as shown in scheme attached below.

                      Furthermore, the ozonide on reduction is convertwed into ketones and aldehydes respectively.

6 0
3 years ago
Read 2 more answers
The density of o2 gas at 16 degrees Celsius and 1.27atm is?
velikii [3]

Answer:

The density of O₂ gas is 1.71 \frac{g}{L}

Explanation:

Density is a quantity that allows you to measure the amount of mass in a given volume of a substance. So density is defined as the quotient between the mass of a body and the volume it occupies:

density=\frac{mass}{volume}

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:

P * V = n * R * T

So, you can get:

\frac{n}{V} =\frac{P}{R*T}

The relationship between number of moles and mass is:

n=\frac{mass}{molar mass}

Replacing:

\frac{\frac{mass}{molar mass} }{V} =\frac{P}{R*T}

\frac{mass}{V*Molar mass} =\frac{P}{R*T}

So:

\frac{mass}{V} =\frac{P*molar mass}{R*T}

Knowing that 1 mol of O has 16 g, the molar mass of O₂ gas is 32 \frac{g}{mol}.

Then:

\frac{mass}{V} =\frac{P*molar mass of O_{2} }{R*T}

In this case you know:

  • P=1.27 atm
  • molar mass of O₂= 32 \frac{g}{mol}.
  • R= 0.0821 \frac{atm*L}{mol*K}
  • T= 16 °C=  289 °K (0°C= 273°K)

Replacing:

density=\frac{mass}{V} =\frac{1.27atm*32\frac{g}{mol}  }{0.0821\frac{atm*L}{mol*K} *289 K}

Solving:

density= 1.71 \frac{g}{L}

<u><em>The density of O₂ gas is 1.71 </em></u>\frac{g}{L}<u><em></em></u>

3 0
3 years ago
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