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REY [17]
3 years ago
12

A gas at 80 kPa occupies a volume of 5 mL. What volume will the gas occupy at 70 kPa

Chemistry
1 answer:
Rashid [163]3 years ago
6 0

Answer:

Volume will the gas occupy at 70 kPa = 5.71

Explanation:

As per the gas law

P_1V_1 = P_2V_2

Here

P_1 = initial pressure of the gas

P_2 = final pressure of the gas

V_1 = Initial volume of the gas

V_2 =  the final volume of the gas

here,

P_1  = 80 kPa

V_1 = 5 mL

P_2 = 70

Substituting the given values in above equation, we get -

80 * 5 = 70 * V_2\\V_2 = 5.71

Volume will the gas occupy at 70 kPa = 5.71

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Someone please answer this...
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Answer:

5446.8 J

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 50 g

Initial temperature (T₁) = 70 °C

Final temperature (T₂) = 192.4 °C

Specific heat capacity (C) = 0.89 J/gºC

Heat (Q) required =?

Next, we shall determine the change in the temperature. This can be obtained as follow:

Initial temperature (T₁) = 70 °C

Final temperature (T₂) = 192.4 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 192.4 – 70

ΔT = 122.4 °C

Finally, we shall determine the heat required to heat up the block of aluminum as follow:

Mass (M) = 50 g

Specific heat capacity (C) = 0.89 J/gºC

Change in temperature (ΔT) = 122.4 °C

Heat (Q) required =?

Q = MCΔT

Q = 50 × 0.89 × 122.4

Q = 5446.8 J

Thus, the heat required to heat up the block of aluminum is 5446.8 J

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