Answer:
Step-by-step explanation:
Use the Law of Cosines
A = arccos[(10²+14²-9.6²)/(2×10×14) ≅ 43.3°
Answer:
540 ft^2.
Step-by-step explanation:
The area of the trapezoid = h/2 (10 + 18) = 14h.
By Pythagoras the height h = √(5^2 - 4^2) = 3.
So the area of the 2 trapezoidal bases = 2 * 14*3
= 84 ft^2.
Now we calculate the area of the four lateral rectangular sides:
= 10*12 + 18*12 + 2*5*12
= 456 ft^2.
Total area = 456 + 54
= 540 ft^2.
Answer:
x = 4
Step-by-step explanation:
35/60 = (5x+1+35)/96
3,360 = 60(5x+36)
56 = 5x+36
20 = 5x
x = 4
Can anyone else figure this out
