Answer: Any real number x as long as 
and 
In other words, anything but 0 or -2/3 is valid.
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Explanation:
Set the denominator equal to zero and solve for x
2(3x^2 + 2x) = 0
3x^2 + 2x = 0
x(3x + 2) = 0
x = 0 or 3x+2 = 0 .... zero product property
x = 0 or 3x = -2
x = 0 or x = -2/3
If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.
Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.
Answer:
1)The rocket hit the ground at 
2)The maximum height of the rocket = 12.468 feet
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given equation
y = -2 x² + 5 x + 7 ...(i)
Differentiating equation (i) with respective to 'x' , we get
Equating zero
⇒ -4 x +5 =0
⇒ -4 x = -5
⇒
<em> The rocket hit the ground at </em><em></em>
<u><em>Step(ii):</em></u>-
...(ii)
Again differentiating equation (ii) with respective to 'x' , we get
The maximum height at x = 
y = -2 x² + 5 x + 7
<em>The maximum height of the rocket = 12.468 feet</em>
Answer:
The probability that there will be a total of 7 defects on four units is 0.14.
Step-by-step explanation:
A Poisson distribution describes the probability distribution of number of success in a specified time interval.
The probability distribution function for a Poisson distribution is:
Let <em>X</em> = number of defects in a unit produced.
It is provided that there are, on average, 2 defects per unit produced.
Then in 4 units the number of defects is, 
.
Compute the probability of exactly 7 defects in 4 units as follows:
Thus, the probability of exactly 7 defects in 4 units is 0.14.
The answer is 340
Explanation:
(g o f)(2) = g(f(2))
f(2) = 6(2)² = 24
g(f(2)) = g(24) = 14(24) + 4 = 336 + 4 = 340
