Why saturated fatty acid can’t create kink ?
1 answer:
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Explanation:
a. Vanillin(4-hydroxy-3-methoxybenzaldehyde):
In its structure hydroxl group will be present on para position of the benzaldehyde ring and methoxy group on meta position.
b. Thymol (2-isopropyl-5-methylphenol):
In its structure isopropyl group will be present on ortho position of the phenol ring and methyl group on meta position.
c. Carvacrol (5-isopropyl-2-methylphenol):
In its structure isopropyl group will be present opposite to methyl group which is present ortho position in a phenol ring.
d. Eugenol (4-allyl-2-methoxyphenol):.
In its structure allyl group will be present on para position of the phenol ring and methoxy group on ortho position.
e. Gallic acid (3,4,5-trihydroxybenzoic acid):
In its structure hydroxyl group will be present on both meta positions and on para position of the benzoic acid ring.
f. Salicyl alcohol (o-hydroxybenzyl alcohol):
In its structure, group is linkedto benzene ring and in respect to that hydroxyl group is present at ortho position of the ring.
The new pressure will be 7.65 atm
<h3>General gas law</h3>The problem is solved using the general gas equation:
P1V1/T1 = P2V2/T2
In this case, P1 = 3.4 atm, V1 = 1500 mL, T1 = 25 , V2 = 2000 mL, and T2 = 75
What we are looking for is P2.
Thus, P2 = P1V1T2/T1V2
= 3.4 x 1500 x 75/25 x 2000 = 382500/50000 = 7.65 atm
More on general gas laws can be found here: brainly.com/question/2542293
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