1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tia_tia [17]
3 years ago
12

Please review the attachment

Chemistry
2 answers:
astra-53 [7]3 years ago
8 0

Answer: The correct answer is -297 kJ.

Explanation:

To solve this problem, we want to modify each of the equations given to get the equation at the bottom of the photo. To do this, we realize that we need SO2 on the right side of the equation (as a product). This lets us know that we must reverse the first equation. This gives us:

2SO3 —> O2 + 2SO2 (196 kJ)

Remember that we take the opposite of the enthalpy change (reverse the sign) when we reverse the equation.

Now, both equations have double the coefficients that we would like (for example, there is 2S in the second equation when we need only S). This means we should multiply each equation (and their enthalpy changes) by 1/2. This gives us:

SO3 —>1/2O2 + SO2 (98 kJ)

S + 3/2O2 —> SO3 (-395 kJ)

Now, we add the two equations together. Notice that the SO3 in the reactants in the first equation and the SO3 in the products of the second equation cancel. Also note that O2 is present on both sides of the equation, so we must subtract 3/2 - 1/2, giving us a net 1O2 on the left side of the equation.

S + O2 —> SO2

Now, we must add the enthalpies together to get our final answer.

-395 kJ + 98 kJ = -297 kJ

Hope this helps!

sergeinik [125]3 years ago
4 0

Answer:

Why did you delete all of my stuff?

Explanation:

I'm just trying to help people and brainly offered me a trusted helpers volunteer. I wanted to become a brainly mod. Why would you delete all of my stuff. I helped a lot of people and this community.  I'm just trying to make people's work easier for them to understand. I also wanted to be a mod to get early volunteer hours for college because a lot of hours looks good on your resume and transcript.

You might be interested in
Which of the following is an example of a
Sergio039 [100]

Answer:

dissolving sugar into water is a physical change

5 0
2 years ago
Choose a sport or sporting play. Describe the types of energy involved in playing the sport. State whether playing the sport is
mrs_skeptik [129]

Answer:

Doing a bungee jumping

Potential energy ---> Kinetic energy

Explanation:

3 0
3 years ago
Discuss two physical and two chemical properties of Nitrogen​
Zigmanuir [339]

Answer:

Nitrogen gas (chemical symbol N) is generally inert, nonmetallic, colorless, odorless and tasteless. Its atomic number is 7, and it has an atomic weight of 14.0067. Nitrogen has a density of 1.251 grams/liter at 0 C and a specific gravity of 0.96737, making it slightly lighter than air.

Explanation:

7 0
3 years ago
A mixture of krypton and argon gas is expanded from a volume of 88.0L to a volume of 100.0L, while the pressure is held constant
Firlakuza [10]

Answer:

-3.28 × 10⁴ J

Explanation:

Step 1: Given data

  • Pressure exerted (P): 27.0 atm
  • Initial volume (Vi): 88.0 L
  • Final volume (Vf): 100.0 L

Step 2: Calculate the work (w) done by the gaseous mixture

We will use the following expression.

w = -P × ΔV = -P × (Vf - Vi)

w = -27.0 atm × (100.0 L - 88.0 L)

w = -324 atm.L

Step 3: Convert w to Joule (SI unit)

We will use the conversion factor 1 atm.L = 101.325 J.

-324 atm.L × 101.325 J/1 atm.L = -3.28 × 10⁴ J

5 0
3 years ago
Consider the second-order reaction:
kirza4 [7]

Answer:

Initial concentration of HI is 5 mol/L.

The concentration of HI after 4.53\times 10^{10} s is 0.00345 mol/L.

Explanation:

2HI(g)\rightarrow H_2(g)+I_2(g)


Rate Law: k[HI]^2


Rate constant of the reaction = k = 6.4\times 10^{-9} L/mol s

Order of the reaction = 2

Initial rate of reaction = R=1.6\times 10^{-7} Mol/L s

Initial concentration of HI =[A_o]

1.6\times 10^{-7} mol/L s=(6.4\times 10^{-9} L/mol s)[HI]^2

[A_o]=5 mol/L

Final concentration of HI after t = [A]

t = 4.53\times 10^{10} s

Integrated rate law for second order kinetics is given by:

\frac{1}{[A]}=kt+\frac{1}{[A_o]}

\frac{1}{[A]}=6.4\times 10^{-9} L/mol s\times 4.53\times 10^{10} s+\frac{1}{[5 mol/L]}

[A]=0.00345 mol/L

The concentration of HI after 4.53\times 10^{10} s is 0.00345 mol/L.

5 0
3 years ago
Other questions:
  • How does thermal energy transfer when a room is heated by a furnace?
    14·2 answers
  • In the reaction C6H12 + __O2 → 6H2O + 6CO2, what coefficient should be placed in front of O2 to balance the reaction? 6 9 18 no
    11·1 answer
  • Which subatomic particle makes the atoms of each elements different?
    5·1 answer
  • Which type of stress causes rocks to fold?
    15·2 answers
  • If 8.82 grams of Aluminum reacts, how many grams of AlCl3 will be produced?
    6·1 answer
  • Which element is most reactive among aluminium, boron, calcium and beryllium? Give reason.
    14·2 answers
  • According to an energy pyramid model, which trophic level is expected have the largest biomass in land ecosystems ?
    9·1 answer
  • PLEASE HELP ME WITH THIS I ONLY HAVE 8 MINUTES I will give you extra points . NUMBER 6
    10·2 answers
  • Describe the trend for atomic radius from left to right across a period. Use atomic
    14·1 answer
  • PLS HELP ME NOW ASAP
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!