Answer: 36.6°C
Explanation:
Given that,
initial pressure of helium (P1) = 1.20 atm
Initial temperature (T1) = 22.0°C
Final temperature (T2) = ?
Final pressure of helium (P2) = 2.00 atm
Since pressure and temperature are given while volume is constant, apply the formula for pressure's law
P1/T1= P2/T2
1.20 atm / 22.0°C = 2.00 atm / T2
Cross multiply
1.20 atm•T2= 2.00 atm•22°C
1.20 atm•T2= 44 atm•°C
Divide both sides by 1.20 atm
1.20 atm•T2/1.20 atm = 44 atm•°C/1.20 atm
T2 = 36.6°C
On top of a clear liquid, a black powder is put. The test tube starts to fizz and bubble, and it also gets hot to the touch. A gas is formed, and then there is a color change from the light and heat it emission.
Light may be absorbed and emitted by atoms and molecules, which allows us to determine the number of energy levels an electron has as well as the distance between those levels. The photon energies that correspond to various colors of light vary. In essence, a photon is a bundle of light. A photon of red light would have less energy than a photon of blue light, for instance. Red and blue have different wavelengths, and since red has a longer wavelength than blue, it has a lower energy. Only in shells, which surround nuclei, do electrons actually exist. Shells are matched to specific energy levels. The process of emission is the release of various colour photons by elements as their atoms decelerate to lower energies. When heated or stimulated, atoms release light.
Learn more about emission here:
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Answer:
Explanation:
Hello,
In this case, we can use the Avogadro's law in order to understand the mole-volume behavior as a directly proportional relationship:
Nonetheless, here we are not given neither the identity of the gas nor its molar or atomic mass, for that reason we can apply the aforementioned equation in terms of mass as we are talking about the same gas:
In such a way, the new volume turns out:
Best regards.
Answer:
93.33 g of Fe
Explanation:
The balanced equation for the reaction is given below:
4Fe + 3O₂ —> 2Fe₂O₃
Next, we shall determine the masses of Fe and O₂ that reacted from the balanced equation. This can be obtained as follow:
Molar mass of Fe = 56 g/mol
Mass of Fe from the balanced equation = 4 × 56 = 224 g
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ from the balanced equation = 3 × 32 = 96 g
SUMMARY:
From the balanced equation above,
224 g of Fe reacted with 96 g of O₂.
Finally, we shall determine the mass of Fe required to react with 40 g of O₂. This can be obtained as follow:
From the balanced equation above,
224 g of Fe reacted with 96 g of O₂.
Therefore, Xg of Fe will react with 40 g of O₂ i.e
Xg of Fe = (224 × 40)/96
Xg of Fe = 93.33 g
Therefore, 93.33 g of Fe is required to react with 40 g of O₂.