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MArishka [77]
3 years ago
6

Brian is buying some tickets for his family to go to a concert. The normal ticket price for one person is £120. There are discou

nts for booking early. Adult tickets have 30% off the normal price. A child's ticket has 60% off the normal price. Brian buys two adult tickets and three child's tickets with the discount. Work out how much he pays.
Mathematics
1 answer:
Lorico [155]3 years ago
8 0

Answer:

30% of 120

= 0.3*120

= 36

120 - 36 = 84 (discounted adult ticket)

60% of 120

= 0.6*120

= 72

120 - 72 = 48 (discounted childrens ticket)

84*2 = 168

48*3 = 144

168 + 144 = 312

he pays 312

Step-by-step explanation:

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vitfil [10]

Answer:

1. -7.5

2. $1

3. 40

Step-by-step explanation:

For number 1, it can be solved by using the PEMDAS method, or see explanation below:

6x - 4x - 36 = 6 - 2x

2x - 36= -2x + 6

4x + 36 = 6

4x = -30

x = -15/2 or -7.5

For number 2, substitute 3 into both equations:

f(x) =1.50(3) + 2.00

and

f(x) = 2.00(3) + 1.50

This would get $6.50 and $7.50, which, if subtracted, gets $1.

For number 3, do something similar to the previous problem. Substitute 3 for x. It would be 5(2^3), or 40.

Hope this helps!

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3 years ago
2. Amanda is reading a 208 page novel for her English
Sloan [31]

Answer:

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Vlad [161]

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3 0
3 years ago
Justin lives 3 2 5 miles from his grandfather's house. Enter the mixed number as a fraction greater than one. 3 2 5 =
elena-s [515]

Answer: \dfrac{17}{5} miles

Step-by-step explanation:

We can express a mixed fraction as an improper fraction.

The process is as follows:

a\dfrac{b}{c}=\dfrac{ac+b}{c}

The given mixed number = 3\dfrac25 miles

This can be represented as

3\dfrac25=\dfrac{3\times5+2}{5}\\\\=\dfrac{15+2}{5}\\\\=\dfrac{15+2}{5}\\\\=\dfrac{17}{5}>1

Hence, the required fraction= \dfrac{17}{5} miles

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Use a proportion to estimate each population. (Please solve both questions, thank you) (I’ll reward you with brainliest :)
hammer [34]

Answer:

<em>Step-by-step explanation:</em>

<em>Step 1. (The capture) Capture a sample  total counted =958, and them back tagged counted=38,total tagged=56 </em>

<em>The idea is to estimate the proportion p = m/N of tagged =102. </em>

<em>Step 2. (The recapture) After everything has settled down, capture a new sample of n fish. Count the number of tagged fish. Suppose that k of them are tagged. </em>

<em>It is reasonable that, k/n would be a good estimante for p = m/N. </em>

<em>Accordingly, for an estimate N of N, se solve the equation m/N= k/n. </em>

7 0
3 years ago
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