Find the area of the figure below (Do Not put the units in your answer)

Mathematics

1 answer:

Contact [7]3 years ago

8 0

Answer:

Step-by-step explanation:

Area of rhombus= (12×9) ÷2

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A batsman scored the following number of runs in six innings:

vlabodo [156]

Answer:

Step-by-step explanation:

The mean or average is calculated by summing each element and then dividing by the number of elements.

We have: 35, 30, 45, 65, 44, and 21.

There are six elements in total.

We find the sum by adding. Hence:

$35+30+45+65+44+21=240$

We will now divide by 6, the number of elements:

$240/6=40$

Therefore, the mean runs scored by the batsman is 40.

Hence, our answer is D.

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3 years ago

Josephine wants to put a wallpaper border around the ceiling of her room. The dimensions are 7 ft and 3 inches and 8 feet and 3

Ilya [14]

Answer:
372inches or 31feet
How to:
7feet and three inches is equal to 87 inches and 8ft and 3 inches is equal to 99 inches. Then you know that both sides have to be multiplied by two because there are four sides in the room. Meaning you have 174in and 198in. Then you add those together to get your answer which is 372. To get back to feet just divide by twelve.

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3 years ago

Which of the following is true? Tangent is positive in Quadrant I. Sine is negative in Quadrant II. Cosine is positive in Quadra

DiKsa [7]

A) Tangent is positive in Quadrant I.

Since sine and cosine are both positive in Quadrant I and tangent is the ratio of sine to cosine, tangent is positive in Quadrant I

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3 years ago

How to graph y=-4|x+2|-5

Elina [12.6K]

$y= -4|x+2| -5 \\ \\x= -6 \Rightarrow y=-4|-6+2|- 5= -4|-4|- 5= -4*4 -5 =\\ \\=-16-5=-21\\ \\ \\x= -4\Rightarrow y=-4|-4+2|- 5= -4|-2|- 5= -4*2 -5 =\\ \\ =-8-5=-13\\ \\ \\x= -2 \Rightarrow y=-4|-2+2|- 5= -4|0|- 5= -4*0 -5 =-5\\ \\ \\x= 0 \Rightarrow y=-4|0+2|- 5= -4|2|- 5= -4*2 -5 =-8-5=-13\\ \\ \\x= 2 \Rightarrow y=-4|2+2|- 5= -4| 4|- 5= -4*4 -5 =-16-5=-21$

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3 years ago

A pyramid has a square base with side s. the hight of the pyramid is 2/3 that of its side. What expression for the volume of the

Bess [88]

i have no clue sorry i cant help you :)

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3 years ago