Our current list has 11!/2!11!/2! arrangements which we must divide into equivalence classes just as before, only this time the classes contain arrangements where only the two As are arranged, following this logic requires us to divide by arrangement of the 2 As giving (11!/2!)/2!=11!/(2!2)(11!/2!)/2!=11!/(2!2).
Repeating the process one last time for equivalence classes for arrangements of only T's leads us to divide the list once again by 2
Answer:
30 cedis
Step-by-step explanation:
todays earning = yesterdays earning * 60/100
50 * 60/100 =30
Answer:



Step-by-step explanation:
Required
Which equals 

Collect like terms


Divide both sides by 2


Collect like terms


Divide both sides by 2


Collect like terms


Divide both sides by -2


Divide both sides by 2

Collect like terms



Divide both sides by 2

Collect like terms


Hence, the equations with the required solution are:



Answer:
(3x+4y-2z=-1)= x=-1/3-4/3y+2/3z
(-x+6y=2z)= x=-7+6y=2z
(4x-2y+3z=27)= x=27/4+1/2-3/4z
Step-by-step explanation:
Look for what 'y' is when t = 1 and t = 2. Go to the graph, look at 1 on the bottom axis and go up till you find the point, then go all the way to the left to see what the y-value is, in this case it should be 1200. If you do the same with t = 2, you will get 2400. So our two ordered pairs are:
(1, 1200), (2, 2400)
We can find the slope of these two points by plugging them into the slope formula:

For points in the form of (x1, y1), (x2, y2). Plug in what we know:

Subtract:

Divide:

This is the slope, so we can write the equation: