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pogonyaev
3 years ago
14

Rectangle LMNO is reflected over the x-axis to create rectangle L'M'N'O'. If a line segment is drawn from point M to point M', w

hich statement would best describe the relationship between segment M M prime and the x-axis? They are diameters of concentric circles. They share the same midpoints. They are perpendicular to each other. They share the same endpoints.
Mathematics
2 answers:
trasher [3.6K]3 years ago
6 0

Answer:I am pretty sure the answer is

C. "They are perpendicular to each other."

Step-by-step explanation:

Dmitry_Shevchenko [17]3 years ago
5 0

Answer: C:they are perpendicular to each

Step-by-step explanation:

i just took the test and got it right

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KATRIN_1 [288]

M-7<6

add 7 to each side

M-7 +7 < 6+7

M < 13

this is true for all values of M less than 13

8 0
3 years ago
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Describe in words the region of R3 reperesented by the equations or inequalities x2+y2+z2≤3
Vaselesa [24]

Answer:

The region represented by the equation is a full sphere of radius √3 centered in the origin of coordinates.

Step-by-step explanation:

<em>In a plane xy, the equation that represents a circle with center in the origin, of radius r is</em>

x^2+y^2=r^2

<em>in R³, or a space xyz, we can represent a sphere with its center in the origin, and of radius r, with the equation</em>

x^2+y^2+z^2=r^2

So, in this problem we have that

3=r^2

which means that the sphere has a radius of √3.

<u>Finally, our equation is an inequality</u>, and the sphere is equal to, and less than, the calculated radius.

Therefore, the sphere is "full" from the surface to its center.

8 0
3 years ago
Joe has 16 pounds of fertilizer for his three gardens. He uses 8/3 of the fertilizer in his first garden and 1/4 of the fertiliz
Natasha2012 [34]

Answer:

3/8

Step-by-step explanation:

3 0
3 years ago
Cos x = sin 34°<br> What is the value of x?<br> Enter your answer in the box.
vredina [299]

\bf \textit{Cofunction Identities} \\\\ sin\left(90^o-\theta\right)=cos(\theta) \qquad cos\left(90^o-\theta\right)=sin(\theta) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ cos(x)=\stackrel{90-56}{sin(\stackrel{\downarrow }{34^o})}\implies cos(\stackrel{\downarrow }{x})=sin(90^o-\stackrel{\downarrow }{56^o})\implies cos(56^o)

3 0
3 years ago
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Heyy!!
rosijanka [135]

<u>Answer:</u>

6^{10}

<u>Step-by-step explanation:</u>

We can use the following rule of surds to solve the problem:

\boxed{a^m \times a^n = a^{m + n}},

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Applying this rule:

6^2 \times 6^8

⇒ 6^{2 + 8}

⇒ \bf 6^{10}

8 0
2 years ago
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