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2 years ago

15

Which statement is true about every rectangular pyramid?

2 answers:

Soloha48 [4]2 years ago

6 0

Answer:

At least two of the lateral faces are congruent.

Step-by-step explanation:

Because the words "at least" are used this means that at a minimum 2 of the faces are congruent. Because the base is in the shape of a triangle, this will definitely be true.

hope this helps:)

Ratling [72]2 years ago

3 0

Answer:

At least two of the lateral faces are congruent.

Step-by-step explanation:

Because the words "at least" are used this means that at a minimum 2 of the faces are congruent. Because the base is in the shape of a triangle, this will definitely be true.

hope this helps:)

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Solve the equation <br> -13/4 -x= 1/2x -1

ale4655 [162]

Answer:

x = 2 or 1/4

Step-by-step explanation:

-13/4 -x= 1/2x -1

Collect like terms

-13/4+1=1/2x+x

Using LCM

(-13+4)/4=(1+2x²)/2x

9/4=(1+2x²)/2x

Cross multiply

9(2x)=4(1+2x²)

18x=4+8x²

Turn into quadratic and solve

8x²-18x+4

Using formulae method

-b±(√b²-4ac)/2a

Where a=8, b= -18 and c=4

(-(-18)±(√(-18)²-4(8)(4))/2(8)

(18±(√324-128))/16

(18±√196)/16

(18±14)/16

(18+14)/16 or (18-14)/16

32/16 or 4/16

2 or 1/4

4 0

3 years ago

Read 2 more answers

0.34 x ? =3.4 what is the value of the missing number

Yakvenalex [24]

Answer:

the answer is 10

Step-by-step explanation:

0.34 x 10 =3.4

3 0

2 years ago

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A family pays $228 for theme park admission. They bought 14 tickets. Adult tickets cost $22 each and kids tickets cost $12 each.

Yanka [14]

Many answers. you have to be more specific

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2 years ago

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Simplify the number into simplest radical form. Use the factor tree to help determine the factors. StartRoot 96 Endroot StartRoo

NikAS [45]

Answer:

$[tex]4608\sqrt{3}$ [/tex]

Step-by-step explanation:

1. $\sqrt{96} *\sqrt{6}* 2*\sqrt{6}*4 *\sqrt{6} *4*\sqrt{3}$

2. $\sqrt{2^{5} *3} \sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$ <em>factoring 96</em>

<em>since $\sqrt{2^{5}*3 } = \sqrt{2^{5} } \sqrt{3}$ </em>

3. $\sqrt{2^{5} } \sqrt{3}\sqrt{6} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>using exponent rule - $(a^{b}) ^{c} = a^{bc}$ </em>

<em> $\sqrt{2^{5} } = 2^{5/2}$ </em>

4. $2^{5/2}\sqrt{3}\sqrt{2*3} *2\sqrt{6}*4\sqrt{6}*4\sqrt{3}$

<em>doing some simple simplification and $4=2^{2}$ and 6=2*3</em>

5. $2^{5/2} \sqrt{3} \sqrt{2} \sqrt{3} *2\sqrt{2} \sqrt{3} *2^{2}\sqrt{2} \sqrt{3}*4\sqrt{3}$

<em>collecting the roots on one side and applying exponent rule</em>

6. $\sqrt{3} \sqrt{3}\sqrt{3} \sqrt{3}\sqrt{2} \sqrt{2}\sqrt{2} *2^{5/2+1+2+2} \sqrt{3}$

<em>Applying exponents rule on all $\sqrt{3}$ and $\sqrt{2}$ </em>

<em>7. $2^{1/2+1/2+1/2} *2^{5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$ </em>

<em>combining all powers of 2</em>

8. $2^{1/2+1/2+1/2+5/2+1+2+2}*3^{1/2+1/2+1/2+1/2+1/2}$

<em>Simplifying</em>

9. $2^{9} *3^{2}\sqrt{3}$

10. $512*9\sqrt{3}$

11. $4608\sqrt{3}$

3 0

3 years ago

Read 2 more answers

Subtract this problem

galina1969 [7]

I think it's 1.90. I am not fully sure about the answer if it's wrong.

6 0

2 years ago