You have two equations.
since the second is already isolated, sub in x-4 for every y in equation 1 so that
![x^{2} - 4 [(x-4)^{2}] =16 ](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20-%204%20%5B%28x-4%29%5E%7B2%7D%5D%20%3D16%0A%20)
expand, collect like terms, factor to find x, then plug x value back into original equation to find y
The idea of grouping is to get the terms in groups that allow you to factor out from each group something that becomes a factor in itself, leaving two factors behind that are alike. Like this: rearrange those terms so they are in this order:
(-70y^2 - 63xy) + (90x^3 + 100yx^2). Now out of the first set we are going to factor out a -7y, and out of the second set we are going to factor out a 10x^2. When we do this, this is what we get: -7y(10y + 9x) + 10x^2(9x + 10y). As you can see, what's inside both sets of parenthesis is the same, just in a different order. We can factor that out now, leaving (9x + 10y)(10x^2 - 7y). And that is factored by grouping.
Answer:
D) 5/2 divided by 8/6
Step-by-step explanation:
Answer:
5.8
Step-by-step explanation:
2.9*2=5.8 give brainliest pls