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Scilla [17]
3 years ago
14

Patton has acquired several other companies. Assume that Patton purchased Kate for $ 9 comma 000 comma 000 cash. The book value

of Kate's assets is $ 18 comma 000 comma 000 ​(market value, $ 20 comma 000 comma 000​), and it has liabilities of $ 14 comma 000 comma 000 ​(market value, $ 14 comma 000 comma 000​). Requirements 1. Compute the cost of goodwill purchased by Patton. 2. Record the purchase of Kate by Patton. Requirement 1. Compute the cost of goodwill purchased by Patton. Purchase price to acquire Kate Market value of Kate's assets Less: Market value of Kate's liabilities Less: Market value of Kate's net assets Goodwill
Business
1 answer:
mel-nik [20]3 years ago
6 0

Answer:

1. Compute the cost of goodwill purchased by Patton.

goodwill = acquisition price - FMV (assets - liabilities)

acquisition price = $9,000,000

FMV assets = $20,000,000

FMV liabilities = $14,000,000

Goodwill = $9,000,000 - ($20,000,000 - $14,000,000) = $9,000,000 - $6,000,000 = $3,000,000

2. Record the purchase of Kate by Patton.

Dr Kate Co. 6,000,000

Dr Goodwill 3,000,000

    Cr Cash 9,000,000

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2 years ago
On December 1 of Year 1, Jones, a self-employed cash basis taxpayer, took out a loan to use in her business. The loan principal
Phoenix [80]

Answer: $6,000

Explanation:

When expenses such as this interest expense are for 12 months or more, the deduction will need to be evenly spread over the period that they apply to. As the loan was to be repaid in 24 months, the interest payment deductions should be evenly spread over 24 months.

= 12,000/24

= $500

That means that for Year 2, the relevant deduction will be for the 12 months in it;

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4 0
4 years ago
A company is selling bonds with a face value of $1,000 to raise money for a plant expansion. The bonds pay a coupon rate of 4% p
Ksivusya [100]

Answer:

10.26%

Explanation:

According to the scenario, computation of the given data are as follow:-

Net sales = $760

Face value of bonds = $1,000

Coupon rate = 4% = $1,000 × 4 ÷ 100

= 40

N = Number of Years = 5 annually = semiannually = 5 × 2

= 10 years

We assume, interest rate = 10% = 0.10

P = Coupon Rate ÷ 2 × (PVIFA,Interest Rate ÷ 2%,No. of Years) + Future Value(PVIF,Interest Rate ÷ 2%, No. of Years)

=$40 ÷ 2 × [1 - 1 ÷ (1 + Interest Rate)N] ÷ Interest Rate + Future Value[1 ÷ (1 + Interest Rate) × N]

=$40 ÷ 2 × [1-1 ÷ (1 + 0.10 ÷ 2)^10] ÷ 0.05 + $1,000 × [1 ÷ (1 + 0.10 ÷ 2)^10]

=$20 × [1 - 1 ÷ (1.05)^10] ÷ 0.05 + $1,000 × [1 ÷ (1.05)^10]

=$20 × [1 -1 ÷ 1.6288946] ÷ 0.05 + $1,000 × [1 ÷ 1.6288946]

= 420 × 7.72173 + $1,000 × 0.613913

= $154.4346 + $613.913

= $768.3476

= $768.35

But the given value is 760, so we assume interest rate = 11%

=$40 ÷ 2 × [1-1 ÷ (1 + Interest Rate)^N] ÷ Interest Rate + Future Value[1 ÷ (1 + Interest Rate)^N]

= $40 ÷ 2 × [1 - 1 ÷(1 + 0.11 ÷ 2)^10] ÷ 0.055 + $1,000 × [1 ÷ (1 + 0.11 ÷ 2)^10]

= $20 × [1 - 1 ÷ (1.055)^10] ÷ 0.055 + $1,000 × [1 ÷ (1.055)^10]

= $20 × [1 - 1 ÷ 1.70814446] ÷ 0.055 + $1000 × [1 ÷ 1.70814446]

= $20 × 7.5376255 + $1,000 × 0.5854306

= $150.75 + $585.43

= $736.18

At the Interest rate of 10% the price is more than $760 and at the Interest rate of 1% the price is less than $760. So the required rate lies in between 10% to 11%.

So required rate  

Yield To Maturity = Lower Interest Rate + (Difference Between Interest Rate) × Higher Price - Received Price ÷ Higher Price - Lower Price

= 1 0+( 11 - 10) × $768.35 - $760 ÷ $768.35 - $736.18

= 10 + 1 × $8.35 ÷ $32.17

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<h3>What is the NPV?</h3>

This is the term that is used to refer to the net present value. This is the value that is calculated as the difference between the cash inflows and out flows for over a time period.

In order to get the NPV we have to make the following calculations for the projects A and B.

We have:

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-900 + 620/1.08 + 395/1.08² + 200/1.08³ + 250/1.08⁴

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we would have

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= 378.98

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4 0
2 years ago
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Zepler [3.9K]

Answer: External secondary data

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External secondary data are data gathered and saved by someone or a body that is not part of one's organization. Sources of External secondary data includes published materials, computerised databases and syndicated services.

Note that how difficult or easier it will be getting a secondary data will depend on the methods used in storing and indexing it.

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