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Ugo [173]
3 years ago
14

Both sound waves and light waves undergo the phenomenon of refraction when they travel form air to water. How is refraction of s

ound waves different from the refraction of light waves?
​
Physics
1 answer:
kiruha [24]3 years ago
7 0

Answer:

<em>Refraction is the change in direction of waves that occurs when waves travel from one medium to another. ... Diffraction is the bending of waves around obstacles and openings. The amount of diffraction increases with increasing wavelength.</em>

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What is HALF PROJECTILE MOTION and what are some examples of it?
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A 1000 kg car makes a turn on a banked curve. The radius is 300 m.
Alenkinab [10]

b) The maximum speed of the car is 47.0 m/s

a) The centripetal force on the car is 7363 N

Explanation:

b)

We have to proceed by solving part b) first. The frictional force between the tires of the car and the road provides the centripetal force that keeps the car in circular motion, therefore we can write:

\mu mg = m\frac{v^2}{r}

where the term on the left is the frictional force while the term on the right is the centripetal force, and where

\mu = 0.75 is the coefficient of friction

m = 1000 kg is the mass of the car

r = 300 m is the radius of the turn

v is the speed of the car

The maximum speed of the car is the speed for which the frictional force is still enough to keep the car in circular motion, so

\mu mg \geq m\frac{v^2}{r}

Therefore, solving for v, we find

v = \sqrt{\mu g r}=\sqrt{(0.75)(9.8)(300)}=47.0 m/s

a)

The centripetal force for an object in circular motion is given by

F=m\frac{v^2}{r}

where

m is the mass of the object

v is its speed

r is the radius of the circular path

For the car in this problem,

m = 1000 kg

v = 47.0 m/s

r = 300 m

Solving for F, we find the force:

F=(1000) \frac{47.0^2}{300}=7363 N

Learn more about circular motion:

brainly.com/question/2562955

#LearnwithBrainly

5 0
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