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ehidna [41]
3 years ago
13

A 1000 kg car makes a turn on a banked curve. The radius is 300 m.

Physics
1 answer:
Alenkinab [10]3 years ago
5 0

b) The maximum speed of the car is 47.0 m/s

a) The centripetal force on the car is 7363 N

Explanation:

b)

We have to proceed by solving part b) first. The frictional force between the tires of the car and the road provides the centripetal force that keeps the car in circular motion, therefore we can write:

\mu mg = m\frac{v^2}{r}

where the term on the left is the frictional force while the term on the right is the centripetal force, and where

\mu = 0.75 is the coefficient of friction

m = 1000 kg is the mass of the car

r = 300 m is the radius of the turn

v is the speed of the car

The maximum speed of the car is the speed for which the frictional force is still enough to keep the car in circular motion, so

\mu mg \geq m\frac{v^2}{r}

Therefore, solving for v, we find

v = \sqrt{\mu g r}=\sqrt{(0.75)(9.8)(300)}=47.0 m/s

a)

The centripetal force for an object in circular motion is given by

F=m\frac{v^2}{r}

where

m is the mass of the object

v is its speed

r is the radius of the circular path

For the car in this problem,

m = 1000 kg

v = 47.0 m/s

r = 300 m

Solving for F, we find the force:

F=(1000) \frac{47.0^2}{300}=7363 N

Learn more about circular motion:

brainly.com/question/2562955

#LearnwithBrainly

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Answer:

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B) Total kinetic energy created by this maneuver is 70.12 Joules.

Explanation:

A) Mass of squid with water = 6.50 kg

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Mass of squid = m_1=6.50 kg- 1.55 kg=4.95 kg

Velocity achieved by squid = v_1=2.60 m/s

Momentum gained by squid = P=m_1v_1

Mass of water = m_2=1.55 kg

Velocity by which water was released by squid = v_2

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P = P'

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B) Kinetic energy does the squid create by this maneuver:

Kinetic energy of squid = K.E  =\frac{1}{2}m_1v_1^{2}

Kinetic energy of water = K.E' = \frac{1}{2}m_2v_2^{2}

Total kinetic energy created by this maneuver:

K.E+K.E'=\frac{1}{2}m_1v_1^{2}+\frac{1}{2}m_2v_2^{2}

=\frac{1}{2}\times 4.95 kg\times (2.60 m/s)^2+\frac{1}{2}\times 1.55 kg\times (8.30 m/s)^2=70.12 Joules

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The  final kinetic energy of the ball is 2.45 J

Explanation:

We can solve this problem by using the law of conservation of energy.

In absence of frictional effect, the mechanical energy of the apple must be conserved during the fall. So we can write:

U_i +K_i = U_f + K_f

where :

U_i is the initial potential energy, at the top

K_i is the initial kinetic energy, at the top

U_f is the final potential energy, at the bottom

K_f is the final kinetic energy, at the bottom

By explicing the potential energy, we can rewrite the equation as:

mgh_i + K_i = mgh_f + K_f

where:

m = 0.5 kg is the mass of the apple

g=9.8 m/s^2 is the acceleration of gravity

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The initial kinetic energy is zero, since the ball starts from rest:

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Therefore we can solve the equation for K_f, the final kinetic energy of the ball:

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Learn more about kinetic energy and potential energy:

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#LearnwithBrainly

3 0
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