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topjm [15]
3 years ago
7

Help me with Economics please and thank you the question is going to be down in a attached file while the answers on here

Physics
2 answers:
Tresset [83]3 years ago
6 0
I think is A or B it depends on like what the trying to answer
Usimov [2.4K]3 years ago
6 0

zoooooooooooooom i am here

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The net torce on an object moving with constant speed in circular motion is in which direction?
aleksley [76]

The correct answer is C) towards the center of the circle.

Although the object is moving at a constant speed it is constantly accelerating due to the constant change in direction as it describes the circular path. This causes a constant change in velocity as velocity is a vector quantity.

For the object to maintain the circular path there has to be centripetal force acting on the object and this centripetal force is directed towards the center of the circle.

6 0
3 years ago
Simplify 6.25 − 8.<br><br>please help
tatyana61 [14]

6.25 - 8 = -1.75

Hope this helps

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7 0
3 years ago
When a sinusoidal wave with speed 20 m/s , wavelength 35 cm and amplitude of 1.0 cm passes, what is the maximum speed of a point
vova2212 [387]

To solve this problem it is necessary to apply the concepts related to frequency as a function of speed and wavelength as well as the kinematic equations of simple harmonic motion

From the definition we know that the frequency can be expressed as

f = \frac{v}{\lambda}

Where,

v = Velocity \rightarrow 20m/s

\lambda = Wavelength \rightarrow 35*10^{-2}m

Therefore the frequency would be given as

f = \frac{20}{35*10^{-2}}

f = 57.14Hz

The frequency is directly proportional to the angular velocity therefore

\omega = 2\pi f

\omega = 2\pi *57.14

\omega = 359.03rad/s

Now the maximum speed from the simple harmonic movement is given by

V_{max} = A\omega

Where

A = Amplitude

Then replacing,

V_{max} = (1*10^{-2})(359.03)

V_{max} = 3.59m/s

Therefore the maximum speed of a point on the string is 3.59m/s

8 0
3 years ago
1. Why is it important to use units in any graph?
Scorpion4ik [409]

Answer:

so its easier to understand for the reader

Explanation:

4 0
3 years ago
Read 2 more answers
A building is 512 m high. What must be the minimum water pressure in a pipe at ground level in order to get water out of a tap i
vivado [14]

Answer:

Pressure =  5 x 10⁶ Pa

Explanation:

Given:

Height of building = 512 m

Find:

Pressure

Computation:

P2 = P1+dgh

P2 = 1 + (1000)(9.8)(512)

P2 = 51.2 atm

Pressure =  5 x 10⁶ Pa

6 0
3 years ago
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