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3 years ago

Help me with Economics please and thank you the question is going to be down in a attached file while the answers on here

Physics

2 answers:

Tresset [83]3 years ago

6 0

I think is A or B it depends on like what the trying to answer

Usimov [2.4K]3 years ago

6 0

zoooooooooooooom i am here

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A stone is thrown at an angle of 30 degrees above the horizontal from the top edge of a cliff with an initial speed of 12 m/s. A

natta225 [31]

v = initial velocity of launch of the stone = 12 m/s

θ = angle of the velocity from the horizontal = 30

Consider the motion of the stone along the vertical direction taking upward direction as positive and down direction as negative.

v₀ = initial velocity along vertical direction = v Sinθ = 12 Sin30 = 6 m/s

a = acceleration of the stone = - 9.8 m/s²

t = time of travel = 4.8 s

Y = vertical displacement of stone = vertical height of the cliff = ?

using the kinematics equation

Y = v₀ t + (0.5) a t²

inserting the values

Y = 6 (4.8) + (0.5) (- 9.8) (4.8)²

Y = - 84.1 m

hence the height of the cliff comes out to be 84.1 m

5 0

3 years ago

A 0.750kg block is attached to a spring with spring constant 13.5N/m . While the block is sitting at rest, a student hits it wit

vazorg [7]

Answer:

A)A=0.075 m

B)v= 0.21 m/s

Explanation:

Given that

m = 0.75 kg

K= 13.5 N

The natural frequency of the block given as

$\omega =\sqrt{\dfrac{K}{m}}$

The maximum speed v given as

$v=\omega A$

A=Amplitude

$v=\sqrt{\dfrac{K}{m}}\times A$

$0.32=\sqrt{\dfrac{13.5}{0.75}}\times A$

A=0.075 m

A= 0.75 cm

The speed at distance x

$v=\omega \sqrt{A^2-x^2}$

$v=\sqrt{\dfrac{K}{m}}\times \sqrt{A^2-x^2}$

$v=\sqrt{\dfrac{13.5}{0.75}}\times \sqrt{0.075^2-(0.075\times 0.75)^2}$

v= 0.21 m/s

5 0

3 years ago

What is Kinetic Energy based on?

jolli1 [7]

Answer:

C. Motion

Explanation:

Hope this helps!

3 0

3 years ago

A container is filled to a depth of 19.0 cm with water. On top of the water floats a 31.0-cm-thick layer of oil with specific gr

IceJOKER [234]

Answer:

Absolute pressure of the oil will be 102822.8 Pa

Explanation:

We have given height h = 31 cm = 0.31 m

Acceleration due to gravity $g=9.8m/sec^2$

Specific gravity of oil = 0.600

So density of oil $\rho =0.6\times 1000=600kg/m^3$

We know that absolute pressure is given by $P=P_0+\rho gh$ , here $P_0=1.01\times 10^5Pa$

So absolute pressure will be equal to $P=1.01\times 10^5+600\times 9.8\times 0.31=102822.8Pa$

So absolute pressure of the oil will be 102822.8 Pa

6 0

3 years ago

Your friend provides a solution to the following problem. Evaluate her solution. The problem: Jim (mass 50 kg) steps off a ledge

Mekhanik [1.2K]

Answer:

No its wrong

Correct compression is 0.41

Explanation:

After jumping from 2m height on spring attached platform platform is compressed a distance x(let).

So work done by gravity on Jim is converted into spring potential energy.

k=8000 N/m

mass of Jim =50 kg

$\frac{1}{2}k(x)^{2} =m*g(2+x)$

$\frac{1}{2}8000(x)^{2} =50*9.8(2+x)$

$8.16x^{2} =2 +x$

Solve this quadratic one solution is positive and other is negative.

positive one is our answer = 0.41 m

5 0

3 years ago