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Orlov [11]
3 years ago
10

Suppose a variable X (systolic blood pressure) is normally distributed with a variance of 36. If approximately 0.25 of the value

s of X are less than 88, what is the mean of X g?
Mathematics
1 answer:
Kazeer [188]3 years ago
3 0

Answer:

92.044

Step-by-step explanation:

The variance = 36

σ² = 36 = 6

The probability that x is less than 88 is equal to 0.25

So probability of (x<z) = 0.25

From the z table, z = -0.674

Using the z formula,

z = x-u/σ

Z = -0.674

X = 88

σ = 6

When we insert these formula we have:

-0.674 = 88 - u/6

6 x -0.674 = 88- u

-4.044 = 88 - u

92.044 = u

Therefore from the calculations above the mean of X is 92.044 and it is approximately 92.

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