Question

What mass of water can be heated from 25.0° C to 50.0° C by the addition of 2825 J of heat energy if the specific heat capacity of water is 4.184 J/goC?
35 g
13 g
27 g
20 g

Answer 1

Answer:

Mass, m = 27g

Explanation:

Given the following data;

Initial Temperature, T1 = 25°C

Final temperature, T2 = 50°C

Quantity of heat = 2825J

Specific heat capacity of water = 4.184

Heat capacity is given by the formula;

$Q = mcdt$

Where,

• Q represents the heat capacity.

• m represents the mass of an object.

• c represents the specific heat capacity of water.

• dt represents the change in temperature.

Making mass, m the subject of formula, we have;

$m = \frac {Q}{cdt}$

Change in temperature, dt = T2 - T1

Change in temperature, dt = 50-25 = 25°C

Substituting into the equation, we have;

$m = \frac {2825}{4.184 * 25}$

$m = \frac {2825}{104.6}$

Mass, m = 27g

Therefore, the mass of water that can be added is 27 grams.