<h2>emf = 9.3 x 10³</h2>
Explanation:
When a conductor moves in the magnetic field , the emf is generated across its ends . Which can be calculated by the relation
emf ξ = B x l x v
here B is the magnetic field strength , l is the length of conductor and v is its velocity .
In our question B = 5.4 x 10⁻⁵ T
l = 2.30 x 10⁴ m and v = 7.5 x 10³
Thus ξ = 5.4 x 10⁻⁵ x 2.30 x 10⁴ x 7.5 x 10³ = 9.3 x 10³ Volt
I think you need to include the Ebola question
Answer:
<h2>
f₀ = 158.12 Hertz</h2>
Explanation:
The fundamental frequency of the string f₀ is expressed as f₀ = V/4L where V is the speed experienced by the string.
where T is the tension in the string and 
is the density of the string
Given T = 600N and = 0.015 g/cm = 0.0015kg/m
The next is to get the length L of the string. Since the string is stretched and fixed at both ends, 200 cm apart, then the length of the string in metres is 2m.
L = 2m
Substituting the derived values into the formula f₀ = V/2L
f₀ = 632.46/2(2)
f₀ = 632.46/4
f₀ = 158.12 Hertz
Hence the fundamental frequency of the string is 158.12 Hertz
Answer:
Tortoise with a mass of 270 kg moving at a velocity of 0.5 m/s
Explanation:
From the question above,
(1) tortoise with a mass of 270 kg moving at a velocity of 0.5 m/s
Mometum = mass×velocity
Momentum = 270×0.5
Momentum = 135 kgm/s
(2) hare with a mass of 2.7 kg moving at a velocity of 7 m/s
Mementum = mass × velocity
Momentum = 2.7×7
Momentum = 18.9 kgm/s
(3) turtle with a mass of 91 kg moving at a velocity of 1.4 m/s
Momentum = mass × velocity
Momentum = 91×1.4
Momentum = 127.4 kgm/s
(4) roadrunner with a mass of 1.8 kg moving at a velocity of 6.7 m/s
Momentum = mass × velocity
Momentum = 1.8×6.7
Momentum = 12.06 kgm/s
From the above, the one with the greatest momentum is tortoise with a mass of 270 kg moving at a velocity of 0.5 m/s
Answer:
106.7 N
Explanation:
We can solve the problem by using the impulse theorem, which states that the product between the average force applied and the duration of the collision is equal to the change in momentum of the object:
where
F is the average force
is the duration of the collision
m is the mass of the ball
v is the final velocity
u is the initial velocity
In this problem:
m = 0.200 kg
u = 20.0 m/s
v = -12.0 m/s
Solving for F,
And since we are interested in the magnitude only,
F = 106.7 N
