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3 years ago

How are wave properties and energy related? give me examples

Physics

1 answer:

klasskru [66]3 years ago

6 0

Answer:

They don’t ‘represent’ anything, they are properties of the wave.

Depending on the type of wave, we experience them as various phenomena. For example, with a sound wave we experience frequency (or wavelength, which is just another way to describe the same property) as the pitch of the sound. We experience amplitude as the loudness of the sound, although due to the characteristics of the ear, frequency also effects perceived loudness.

If the wave is a light wave, we experience the frequency (wavelength) as the colour of the light, and the amplitude as the brightness of the light.

For many waves, we don’t perceive them at all (e.g. radio waves).

For ocean waves, frequency is the time for each peak or trough to reach us, and amplitude is how tall the wave is.

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Which one?? please someone quick!

LiRa [457]

Answer:

i think its second law of motion.

Explanation:

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3 years ago

Read 2 more answers

Hypothetical structures

jeka94

Answer : Hypothetical situations are situations that we imagine. There are specific English grammar structures, phrases and forms to express hypothetical situations. Here are some examples of some hypothetical situations using a wide variety of forms.

Step by step explanation :

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3 years ago

What is the smallest resistance you can make by combining them?

Luda [366]

Answer:

166.67 ohm

Explanation:

Complete statement of the question is :

You have a collection of six 1.0 kO resistors. What is the smallest resistance you can make by combining them?

When we connect resistors in parallel, the combination resistance is always smaller than the smallest resistance value we combine.

Parallel Combination of resistances is given as

$\frac{1}{R_{p}} = \frac{1}{R_{1}} +\frac{1}{R_{2}} +\frac{1}{R_{3}} + ....$

where

$R_{p}$ = Equivalent resistance

and $R_{1} , R_{2}, R_{3}$ are resistances in parallel.

So for the above question, we have

$R_{1} = R_{2} = R_{3} = R_{4} = R_{5} = R_{6} = 1 kohm = 1000 ohm$

So parallel combination is given as

$\frac{1}{R_{p}} = \frac{1}{R_{1}} +\frac{1}{R_{2}} +\frac{1}{R_{3}} +\frac{1}{R_{4}} +\frac{1}{R_{5}} +\frac{1}{R_{6}}\\\frac{1}{R_{p}} = \frac{1}{1000} +\frac{1}{1000} +\frac{1}{1000} +\frac{1}{1000} +\frac{1}{1000} +\frac{1}{1000}\\R_{p} = \frac{1000}{6} \\R_{p} = 166.67 ohm$

So the smallest resistance is 166.67 ohm

8 0

4 years ago

A 2.40 kg snowball is fired from a cliff 7.69 m high. The snowball's initial velocity is 13.0 m/s, directed 49.0° above the hori

Crazy boy [7]

Answer:

a) W = 180.87 J , b) ΔU = -180.87 J , c) ΔU = -180.87 J

Explanation:

a) Work is defined as

W = F .ds

Where bold indicates vectors, we can write the scalar product

W = F s cos θ

Where the angle is between force and displacement.

The force of gravity is the weight of the body, which is directed downwards and the displacement thickens the tip of the cliff at the bottom, so that it is directed downwards, therefore the angle is zero degrees

W = $F_{g}$ y

W = m g y

For this problem we must fix a reference system, from the statement it is established that the system is placed at the base of the cliff, so that final height is zero and the initial height (y₀ = 7.69m)

W = 2.40 9.8 (7.69-0)

W = 180.87 J

b) The potential energy is

U = mg y

The change in potential energy,

ΔU = $U_{f}$ - U₀

ΔU = mg ( $y_{f}$ - y₀)

ΔU = 2.4 9.8 (0 -7.69)

ΔU = -180.87 J

c) in this case we change the reference system to the height of the cliffs, for this configuration

y₀ = 0

$y_{f}$ = -7.69 m

ΔU = 2.4 9.8 (-7.69 -0)

ΔU = -180.87 J

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3 years ago

Why does the distance and time increase when the object is moving?

Inessa05 [86]

Answer:

Because if something is moving at a steady speed, it means we expect the increase in distance in a given time: Time is increasing to the right and distance is increasing steadily with time.

4 0

3 years ago