All categories

3 years ago

How are wave properties and energy related? give me examples

Physics

1 answer:

klasskru [66]3 years ago

6 0

Answer:

They don’t ‘represent’ anything, they are properties of the wave.

Depending on the type of wave, we experience them as various phenomena. For example, with a sound wave we experience frequency (or wavelength, which is just another way to describe the same property) as the pitch of the sound. We experience amplitude as the loudness of the sound, although due to the characteristics of the ear, frequency also effects perceived loudness.

If the wave is a light wave, we experience the frequency (wavelength) as the colour of the light, and the amplitude as the brightness of the light.

For many waves, we don’t perceive them at all (e.g. radio waves).

For ocean waves, frequency is the time for each peak or trough to reach us, and amplitude is how tall the wave is.

You might be interested in

7. How much work is done in moving a charge of 10 micro coulombs 1 meter along an equipotential of 10 volts?

Neko [114]

It takes work to push charge through a change of potential.
There's no change of potential along an equipotential path,
so that path doesn't require any work.

8 0

3 years ago

Read 2 more answers

An object is moving at a constant velocity of 10 m/s for 5 seconds. What is

german

initial velocity (u)=0m/s

final velocity (v)=10m/s

time( t)=5s

acceleration (a)=v-u÷t

acceleration (a)=10-0÷5

acceleration (a)=10÷5

acceleration (a)=2

therefore acceleration (a)=2m/s

3 0

3 years ago

Which statement best describes the movement of electrical current when a capacitor is used in a circuit?

lukranit [14]

Answer:

The discharge of a capacitor changes the direction of the current

Explanation:

Capacitor is used to store charges. Changing and discharging a capacitor changes the direction of the current.

When a capacitor is charging, current flows towards the positive plate and away from the negative plate. When the capacitor is discharging, current flows away from the positive and flows towards the negative plate, in the opposite direction. During these two processes (charging and discharging), it can be seen that the direction of the current is changed.

Therefore, the discharge of a capacitor changes the direction of the current

5 0

3 years ago

For question #13, use the following picture: 13. The picture is a model of a nitrogen atom. What is incorrect about the atomic o

valentinak56 [21]

the electrons should be in the outer valence levels/shells.

8 0

3 years ago

A plane electromagnetic wave, with wavelength 4.1 m, travels in vacuum in the positive direction of an x axis. The electric fiel

marusya05 [52]

(a) $7.32\cdot 10^7 Hz$

The frequency of an electromagnetic waves is given by:

$f=\frac{c}{\lambda}$

where

$c=3.0\cdot 10^8 m/s$ is the speed of light

$\lambda=4.1 m$ is the wavelength of the wave in the problem

Substituting into the equation, we find

$f=\frac{3.0\cdot 10^8 m/s}{4.1 m}=7.32\cdot 10^7 Hz$

(b) $4.60\cdot 10^8 rad/s$

The angular frequency of a wave is given by

$\omega = 2\pi f$

where

f is the frequency

For this wave,

$f=7.32\cdot 10^7 Hz$

So the angular frequency is

$\omega=2\pi(7.32\cdot 10^7 Hz)=4.60\cdot 10^8 rad/s$

(c) $1.53 m^{-1}$

The angular wave number of a wave is given by

$k=\frac{2\pi}{\lambda}$

where

$\lambda$ is the wavelength of the wave

For this wave, we have

$\lambda=4.1 m$

so the angular wave number is

$k=\frac{2\pi}{4.1 m}=1.53 m^{-1}$

(d) $1.03\cdot 10^{-6}T$

For an electromagnetic wave,

$E=cB$

where

E is the magnitude of the electric field component

c is the speed of light

B is the magnitude of the magnetic field component

For this wave,

E = 310 V/m

So we can re-arrange the equation to find B:

$B=\frac{E}{c}=\frac{310 V/m}{3\cdot 10^8 m/s}=1.03\cdot 10^{-6}T$

(e) z-axis

In an electromagnetic wave, the electric field and the magnetic field oscillate perpendicular to each other, and they both oscillate perpendicular to the direction of propagation of the wave. Therefore, we have:

- direction of propagation of the wave --> positive x axis

- direction of oscillation of electric field --> y axis

- direction of oscillation of magnetic field --> perpendicular to both, so it must be z-axis

(f) 127.5 W/m^2

The time-averaged rate of energy flow of an electromagnetic wave is given by:

$I=\frac{E^2}{2\mu_0 c}$