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andreyandreev [35.5K]
2 years ago
11

How are wave properties and energy related? give me examples

Physics
1 answer:
klasskru [66]2 years ago
6 0

Answer:

They don’t ‘represent’ anything, they are properties of the wave.

Depending on the type of wave, we experience them as various phenomena. For example, with a sound wave we experience frequency (or wavelength, which is just another way to describe the same property) as the pitch of the sound. We experience amplitude as the loudness of the sound, although due to the characteristics of the ear, frequency also effects perceived loudness.

If the wave is a light wave, we experience the frequency (wavelength) as the colour of the light, and the amplitude as the brightness of the light.

For many waves, we don’t perceive them at all (e.g. radio waves).

For ocean waves, frequency is the time for each peak or trough to reach us, and amplitude is how tall the wave is.

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A heating element on an electric range operating at 200. v has a resistance of 32.0 ohms. the current drawn by the element is
LenaWriter [7]

Answer:

6.25 A

Explanation:

We cant find the current drawn by the element by using Ohm's law:

V=RI

where

V is the potential difference across the resistance of the element

R is the resistance

I is the current

In this problem, we know

V = 200 V

R=32.0 \Omega

Therefore we can re-arrange the equation and solve for the current:

I=\frac{V}{R}=\frac{200}{32}=6.25 A

4 0
3 years ago
I have this sheet and I don’t understand any of it at all
katen-ka-za [31]

I know this probably is not what you are looking for, but this is what I would suggest.

Write down on the side what values they are giving you and the corresponding variable used for that value.

Like for the first question, they give you mass is 3000kg.

On the side write

m = 3000kg

m is the variable used for mass

Then list any other variables they give you in the question and then what you are trying to look for.

a = 2m/s^2

F = ?

a is the variable for acceleration and F is the variable for force.

So now you have:

m = 3000kg

a = 2m/s^2

F = ?

You have a and m, and you are looking for F (force), you know that because it asks "with what force".

Also note, that you have to know what the variable is based on the units and you likely have some type of formula sheet with all of them listed.

You can use the variables and what is unknown to match it to a formula that will solve for the unknown variables. Also note, that it might not always be simply a=b+c, you may know what "a" and "b" are, but they may ask for c so you will have to rearrange the formula with some simple algebra.

This question however is simple. You can see you are going to use the formula

F=ma.

So now just substitute in your variables to solve for F.

(3000kg)(2m/s^2) = 6000N

<u>Make sure to write the units</u> which are probably on your formula sheet as well. Force is measured in Newtons, so you use the unit N.

Also note, if they gave you mass in grams (another unit), you cannot use that in the formula (your formula sheet would tell you the unit it must be in), so you would have to convert it to kg.

Hope this helps as a starting point. I don't intend to do your homework for you, but explain a process you can use to help you do it on your own.

3 0
3 years ago
A +2.2 x 10-9 C charge is on the axis ar x= 1.5 m, a +5.4 x 10-9 C charge is on the x-axis at x= 2.0 m, and a+3.5 x 10-9 C charg
lisov135 [29]

The net force on the charge at the origin is -1.2×10-8

<u>Explanation:</u>

Solving the problem,

  • Draw the x-axis and the locations of the given three charges.
  • The forces applied on the charge at the origin and there are two of them, and since all the changes are positive, all the forces are repulsive.
  • we have the formula, F = kq1Q/r².
  • F1 = kq1Q/r²1 = (9.0*109Nm²/C²)(2.2*10^-9C)(3.5*10^-9C)/(1.5m)² = 31*10-9N = 3.1*10-8N.  F1 points to the right (+x direction).
  • F2 = kq2Q/r²2 = (9.0*109Nm²/C²)(5.4*10^-9C)(3.5*10^-9C)/(2.0m)² = 43*10^-9N = 4.3*10^-8N.
  • F2 points to the left (-x direction).
  • To find the net force we have to subtract the force F1 and force F2 .
  • The net force is F(origin) = F1 - F2 = -1.2×10-8N.

<u></u>

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5 0
3 years ago
If the absolute pressure of a gas is 550.280 kPa, its gage pressure is
Gwar [14]
If the absolute pressure of a gas is 550.280 kPa, its gage pressure is <span> a. 101.325 kPa.
b. 448.955 kPa.
c. 651.605 kPa.
d. 277.280 kPa.</span>

The answer is B.
6 0
3 years ago
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A ball bounces on the ground. How do the ball and the ground act on each other?(1 point)
liubo4ka [24]

Answer: A is your best answer.

Explanation:

It should be A because the when the ball bounces on the ground the ground will give it force to bounce again but also it wont go as high as it first did. Hope this helps:))

3 0
3 years ago
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