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baherus [9]
3 years ago
14

Suppose a thin conducting wire connects two conducting spheres. A negatively charged rod is brought near one of the spheres, the

wire between them is cut, and the charged rod is taken away. Which one of the following is true? a. The spheres will attract each other. b. The spheres will repel each other. c. There will be no electrostatic force between the spheres
Physics
1 answer:
dangina [55]3 years ago
4 0

Answer:

a. The spheres will attract each other.

Explanation:

When two conducting spheres are connected by a conducting wire and a negatively charged rod is brought near it then this will induce opposite (positive) charge at the nearest point on the sphere and by the conservation of charges there will also be equal amount of negative charge on the farthest end of this conducting system this is called induced polarization.

  • When the conducting wire which joins them is cut while the charged rod is still in proximity to of one of the metallic sphere then there will be physical separation of the two equal and unlike charges on the spheres which will not get any path to flow back and neutralize.
  • Hence the two spheres will experience some amount of electrostatic force between them.
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3 years ago
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The energy levels of a particular quantum object are -11.7 eV, -4.2 eV, and -3.3 eV. If a collection of these objects is bombard
gogolik [260]

To solve this problem it is necessary to apply an energy balance equation in each of the states to assess what their respective relationship is.

By definition the energy balance is simply given by the change between the two states:

|\Delta E_{ij}| = |E_i-E_j|

Our states are given by

E_1 = -11.7eV

E_2 = -4.2eV

E_3 = -3.3eV

In this way the energy balance for the states would be given by,

|\Delta E_{12}| = |E_1-E_2|\\|\Delta E_{12}| = |-11.7-(-4.2)|\\|\Delta E_{12}| = 7.5eV\\

|\Delta E_{13}| = |E_1-E_3|\\|\Delta E_{13}| = |-11.7-(-3.3)|\\|\Delta E_{13}| = 8.4eV

|\Delta E_{23}| = |E_2-E_3|\\|\Delta E_{23}| = |-4.2-(-3.3)|\\|\Delta E_{23}| = 0.9eV

Therefore the states of energy would be

Lowest : 0.9eV

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8 0
4 years ago
1) A force of 157 N is applied to a box 25o above the horizontal. If it is applied over a distance of 14.5 m how much work is do
vfiekz [6]

#1

Work done is given by

W = F.d cos\theta

here we know that

F = 157 N

d = 14.5

\theta = 25^0

now from the above formula

W = (157)(14.5)cos25 = 2063.2 J

#2

By energy conservation

Initial total potential energy of egg = final total kinetic energy of egg

mgh = \frac{1}{2}mv^2

v = \sqrt{2gh}

v = \sqrt{2(9.8)(8.2)}

v = 12.7 m/s

#3

By momentum conservation we know that

m_1v_1 = (m_1 + m_2)v

215(9.5) = (215 + 19.7) v

v = \frac{215 (9.5)}{215 + 19.7}

v = 8.7 m/s

#4

by momentum conservation we know that

m_1v_1 + m_2v_2 = (m_1 + m_2) v

let direction of velocity of Jay Z car motion is positive direction

now we will say

1100(-20) + 1475v = (1100 + 1475)(7)

1475 v = 2575(7) + 1100(20)

v = 27.14 m/s

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#5

Tension force in the string will be centripetal force

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T = \frac{mv^2}{R}

here we know that

m = 0.63 kg

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Two objects are in freefall. Object A experiences a gravitational force of
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<u>Answer:</u>

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<u>Explanation :</u>

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Weight is the force acting on a body of some mass, and the formula for finding the weight of a body is- Weight = mass × acceleration due to gravity(g).

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3 years ago
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masya89 [10]

Answer:

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