It is E X= 22
J LINE SUPPLEMENTARY ANGLE so
the angle is = 180 - (5x-16 ) = 180-5x +16 =196 -5x ( angle in the triangke )
the other angle in the triangle = 50 ( alt interior angles line l parallel m
then we took the triangle sum = 180
<span>196 -5x </span> + 2x +50 = 180
so x = 22
2^2x=5^x−1
Take the log pf both sides:
ln(2^2x) = ln(5^x-1)
Expand the logs by pulling the exponents out:
2xln(2) = (x-1)ln(5)
Simpligy the right side:
2xln(2) = ln(5)x - ln(5)
Now solve for x:
Subtract ln(5)x from both sides:
2xln(2) - ln(5)x = -ln(5)
Factor x out of 2xln(2)-ln(5)x
x(2ln(2) - ln(5)) = -ln(5)
Divide both sides by (2ln(2) - ln(5))
X = - ln(5) / (2ln(2) - ln(5))
Mona mona mona mona monq mona
Answer:
Your answer would be 5400.
Step-by-step explanation:
You have to follow PEMDAS for this one. You will start within the parenthesis and add 10 and 20 together to get 30. You would then times that by 20 and get 600. Finally, you would mulitply that by 9 and get 5400 as your answer..
