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suter [353]
3 years ago
15

HARD QUADRATICS!!!! A quadratic of the form $-2x^2 + bx + c$ has roots of $x = 3 + \sqrt{5}$ and $x = 3 - \sqrt{5}.$ The graph o

f $y = -2x^2 + bx + c$ is a parabola. Find the vertex of this parabola.
Mathematics
1 answer:
iren2701 [21]3 years ago
5 0

Answer:

hold up this will take a min to work out

Step-by-step explanation:

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Multiply x(x 5) how to find the answer
PilotLPTM [1.2K]
I hope this helps you



x.x^5



x^1+5



x^6
8 0
3 years ago
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What is 2 5/12 -(-2 1/6) Express the answer in simplest form.
VladimirAG [237]
Answer:
= 29/12 − -13/6

<span>= ((29 × 6) − (-13 × 12)) / (12 × 6) </span>

= (174 - -156) / 72

= 330/72

= 55/12

<span>= 4 7/12</span>
3 0
3 years ago
1. Michael buys a chocolate bar which has 50% extra free. The chocolate bar usually weighs 200g. (a) How much extra chocolate do
KiRa [710]

Answer:

1/2 more chocalte or 50% more or 100g more

300g is the new weight

Step-by-step explanation:

200/2=100(50%)

100+200=300g

5 0
2 years ago
Suppose that 5 J of work is needed to stretch a spring from its natural length of 30 cm to a length of 39 cm.
vesna_86 [32]

Answer

given,

work = 5 J

spring stretch form 30 cm to 39 cm

W = \dfrac{1}{2}kx^2

x = 0.39 - 0.30 = 0.09 m

5 = \dfrac{1}{2}k\times 0.09^2

k = \dfrac{5\times 2}{0.09^2}

k = 1234.568 N/m

a) work when spring is stretched from  32 cm to 34 cm

x₂= 0.34 -0.30 = 0.04 m

x₁ = 0.32 - 0.30 = 0.02

W = \dfrac{1}{2}k(x_2^2-x_1^2)^2

W = \dfrac{1}{2}\times 1234.568 \times (0.04^2-0.02^2)^2

W = 0.741 J

b) F = k x

  25 = 1234.568 × x

     x = 0.0205 m

     x = 2.05 cm

3 0
3 years ago
Write the domain and the range of the function as an inequality, using set notations, and using interval notation. Also describe
matrenka [14]

Answer:

Step-by-step explanation:

The end behavior notation is at (4,3)

8 0
3 years ago
Read 2 more answers
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