HARD QUADRATICS!!!! A quadratic of the form $-2x^2 + bx + c$ has roots of $x = 3 + \sqrt{5}$ and $x = 3 - \sqrt{5}.$ The graph o
1 answer:
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Answer:
answer is c
Step-by-step explanation:
0=theta symbol
SOH CAH TOA
SOH= Sin0=Oppisite/hypotnuse
CAH= Cos0=Adjecent/Hypotnuse
TOA= Tan0=Oppisite/Adjecent
Answer:
I believe the slope would be -2
Step-by-step explanation:
The line goes <u>down 2</u> boxes and <u>over 1</u> box before it intersects with another point. Knowing slope = , we know that slope =
which is equal to -2.