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Serhud [2]
3 years ago
10

Find upper and lower limit of a weight of a cotton reel which is 1.56g nearst to mg

Mathematics
1 answer:
Papessa [141]3 years ago
4 0

Answer: the lower limit is 1.555g and the upper limit is 1.564g

Step-by-step explanation:

a mg is:

1mg = 0.001g

Then we need to look at the third digit after the decimal point.

Then the weight 1.56g is rounded around this.

Remember that if the third digit after the decimal point is 5 or bigger, then we round up.

if the third digit is smaller than 5, then we round down.

Now, the maximum possible value of this weight is when the third digit is equal to 4 (4 mg) where because it is smaller than 5, we round it down to 1.56g

Then the maximum is 1.564g

And the minimum value is when we have:

w = 1.555g

Because the third digit is a 5, we round it up to 1.56g.

So the lower limit is 1.555g and the upper limit is 1.564g

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Prove that (a-b) x (a+b)=2a x b is true.<br> (a and b are vectors)
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Which polynomial represents the difference below?
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Answer:

c

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3 years ago
Which of the following measurements could be the side lengths of a right triangle?
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Answer:

C. 10in 24in 26in

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Angle ∠B = 22.62° = 22°37'12" = 0.39479 rad

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Median ma = 15.6205  

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