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irina1246 [14]
3 years ago
13

Bryce can build 3 benches in 11 hours. How many hours will it take him to build 12 benches?

Mathematics
1 answer:
gayaneshka [121]3 years ago
6 0
0.363636363636364 benches
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Answer:

The answer is 3(+1)(+2)

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The function y= 19,800/x is a rational function. Use this function to answer each question. What are the asymptotes of the funct
Ilya [14]

Answer:

Step-by-step explanation:

Given the function y = 19800/x

Vertical asymptote occurs at when f(x) = 0 where;

f(x) is the denominator of the given function.

From the expression given: f(x) = x

Since f(x) => 0, hence x = 0

To get the horizontal asymptote, we will look at the degree of the numerator and denominator. If the degree of numerator is less than the denominator, the horizontal asymptote will be zero. From the function, we can see that the degree of the numerator is zero (being a constant) and that of the denominator is 1.

Since 0<1, hence the horizontal asymptote is 0

x = 0, y = 0

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2 years ago
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Is the function even or odd?
sweet [91]

Answer:

f(\theta)=\cos(\theta) is an even function.

Step-by-step explanation:

Recall when it means when a function is even or odd. An even function has the following property:

f(-x)=f(x)

And an odd function has the following property:

f(-x)=-f(x)

So, let's test some values for cos(x).

Let's use π/3:

f(\pi/3)=\cos(\pi/3)

From the unit circle, was can see that this is 1/2 (refer to the x-coordinate).

Now, let's find -π/3. This is the same as 5π/3. Thus:

f(-\pi/3)=\cos(-\pi/3)

And again from the unit circle, we can see that this is 1/2.

Therefore, despite the negative, the function outputs the same value.

Cosine is an even function.

Notes:

Cosine is an even function and sine is an odd function. It's helpful to remember these as they can help you solve some trig problems!

6 0
3 years ago
At the beginning of the school year, there were three 4th grade classes. Mrs. Smith’s class had 19 children, Mr. Day’s class has
Blababa [14]
43 19+17+20 = 56 - 13 = 43
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3 years ago
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How do you do this please help
nadezda [96]
You can create the equation 1.20x + 2.50y = 300
Where 1.20 is the price of each vinca flower, x is how many vinca you will buy, 2.50 is the price of each phlox flower, y is how many plhox you will buy and 300 is how much money you have.

To get three combinations of how many plhox and vinca flowers you ( or the gardner can buy) with 300, you can just take a random value for x or y, apply it to the equation and then solve the equation for the other
variable ( x or y).
This means:
Pick a number of how many flower you will get of ONE type of flower ( ONLY ONE)
The gardner will not get any Vinca flowers, then x = 0
( as x = how many vinca flower the gardner will get)
now apply 0 to x ( this means substitute x with 0)

(1.20)(0) + 2.50y = 300
Since any number x 0 is 0, the equation will be
0 + 2.50y = 300 or just 2.50y = 300

Now to solve an equation we just need to isolate the variable (y) on one side of the equation and the value on the other.
We can do that by dividing both sides of the equation, so 2.50y turns into 2.50/2.50 times y which is just y.

2.50/2.50 y = 300/2.50
y = 120
And since we chose the value for how many vincas we would buy, we have the x value as well ( 0)
x = 0

So 1 combination can be: 0 Vinca and 120 Plhox

Combination #2 ( I ll stop explaining the steps since I already explained how to do it)

y = 0 ( I chose not to buy any Plhox)

1.20x + (2.50)(0) = 300
1.20x = 300
1.20/120x = 300/120x
x = 25
y= 0
Combination 2: 25 Vincas and 0 plhox

Combination #3:
x = 100 ( I chose to buy 10 vincas)
(1.20)(100) + 2.50y = 300
120 + 2.50y = 300
( I didnt explain thow to isolate a variable in this situation so ill explain it: to isolate this esquation we can subtract 12 from both sides of the equation so 12 cancels out. We need to do it on both sides because otherwise the first side wouldnt be equal to the other sode, and that wouldnt be an equation)

120 - 120 + 2.50y = 300 - 120
2.50y = 180
y = 72
x = 100

Combination 3: 100 Vinca and 72 Plox

I know this is long but I hope it was helpful to you if you didnt know how to solve equations :)


3 0
3 years ago
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