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3 years ago

Enter the numb bee that belongs in the green box

Mathematics

1 answer:

bulgar [2K]3 years ago

7 0

this is the answer

210.28

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1. f(x) = 2x + 6 Evaluate f(2)

fredd [130]

1) f(x)=2x+6
f(2)=2(2)+6
=4+6
=10

2)f(x)=3x
f(a+1)=3(a+1)
=3a+3
3)f(x)=3x-1 and g(x)=5x+3

f(2)=3(2)-1
f(2)=6-1
=5
g(3)=5x+3
=5(3)+32
=15+3
=18

f(2)+f(3)=5+18
=23.

7 0

3 years ago

Read 2 more answers

Cassie received a 20%-off coupon and a $10-off coupon from a department store. She visits the department store during a tax-free

UNO [17]

Answer:

B. The original purchase total must be at most to $44 before the discounts are applied.

Step-by-step explanation:

Solve the inequality by adding $10, then dividing by 0.8.

0.8x -$10 ≤ $25.20

0.8x ≤ $35.20 . . . . . . . . add $10

x ≤ $35.20/0.8 . . . . . . . divide by 0.8

x ≤ $44 . . . . . . . . . the before-discount purchase must be at most $44

4 0

3 years ago

The store had a special on apples, 4 pounds for $2.80. The store's special on oranges was 3 pounds for $2.58. Which of the follo

Viktor [21]

Answer:

Step-by-step explanation:

Hope this helps!!

8 0

2 years ago

Read 2 more answers

1. Does this equation represent growth or decay?<br> A (t) = 800(1.21)

Sholpan [36]

Answer:Decay

Step-by-step explanation: because of perenthesis

6 0

2 years ago

Read 2 more answers

The following lists the joint probabilities associated with smoking and lung disease among 60-to-65 year-old men. Has Lung Disea

Anna71 [15]

Answer:

4.11% probability that he has lung disease given that he does not smoke

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Does not smoke

Event B: Lung disease

Lung Disease/Nonsmoker 0.03

This means that $P(A \cap B) = 0.03$

Lung Disease/Nonsmoker 0.03

No Lung Disease/Nonsmoker 0.7

This means that $P(A) = 0.03 + 0.7 = 0.73$

What is the probability of the following event: He has lung disease given that he does not smoke?

$P(B|A) = \frac{0.03}{0.73} = 0.0411$

4.11% probability that he has lung disease given that he does not smoke

5 0

3 years ago