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Dimas [21]
3 years ago
8

Plot x and y intercept of Y=1/3x-1

Mathematics
1 answer:
olganol [36]3 years ago
5 0

The x intercept is 3 and the y intercept is -1.

The graph would look something like the image below.

Hope this helped you!

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Anna baked 3 batches of cookies with c cookies in each batch. She then ate 8 cookies! How many cookies does Anna have left? Writ
borishaifa [10]

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3 years ago
Find the range of the given data set.<br> -4, -3, -1, -1, 0, 1
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3 0
2 years ago
Find the perimeter of the polygon with vertices A(-6,-4), B(-3,6), C(4,0), and D(2,-1)?
EleoNora [17]
Check the picture below.

so the perimeter of the polygon is the sum of all its sides, namely, AB + BC + CD + DA.

now, let's check how long each side is,

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&A&(~{{ -6}} &,&{{ -4}}~) &#10;%  (c,d)&#10;&B&(~{{ -3}} &,&{{ 6}}~)&#10;\end{array}&#10;\\\\\\&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\\\&#10;-------------------------------\\\\&#10;AB=\sqrt{[-3-(-6)]^2+[6-(-4)]^2}&#10;\\\\\\&#10;AB=\sqrt{(-3+6)^2+(6+4)^2}&#10;\\\\\\&#10;AB=\sqrt{3^2+10^2}\implies \boxed{AB=\sqrt{109}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&B&(~{{ -3}} &,&{{6}}~) &#10;%  (c,d)&#10;&C&(~{{ 4}} &,&{{ 0}}~)&#10;\end{array}&#10;\\\\&#10;-------------------------------\\\\&#10;BC=\sqrt{[4-(-3)]^2+[0-6]^2}\implies BC=\sqrt{(4+3)^2+(0-6)^2}&#10;\\\\\\&#10;BC=\sqrt{7^2+(-6)^2}\implies \boxed{BC=\sqrt{85}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&C&(~{{ 4}} &,&{{0}}~) &#10;%  (c,d)&#10;&D&(~{{ 2}} &,&{{ -1}}~)&#10;\end{array}&#10;\\\\&#10;-------------------------------\\\\&#10;CD=\sqrt{(2-4)^2+(-1-0)^2}\implies CD=\sqrt{(-2)^2+(-1)^2}&#10;\\\\\\&#10;\boxed{CD=\sqrt{5}}\\\\&#10;-------------------------------

\bf ~~~~~~~~~~~~\textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{ccccccccc}&#10;&&x_1&&y_1&&x_2&&y_2\\&#10;%  (a,b)&#10;&D(~{{ 2}} &,&{{-1}}~) &#10;%  (c,d)&#10;&A&(~{{ -6}} &,&{{ -4}}~)&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;DA=\sqrt{[-6-2]^2+[-4-(-1)]^2}\\\\\\ DA=\sqrt{(-6-2)^2+(-4+1)^2}&#10;\\\\\\&#10;DA=\sqrt{(-8)^2+(-3)^2}\implies \boxed{DA=\sqrt{73}}

sum those sides up, and that's the perimeter of the polygon.

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2 years ago
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