Hello!
6.
Since the area is that of a square, you know that all side lengths are the same.
Area is base times height (A = bh), but since base and height are the same for a square, you get the formula A = a².




The length of the side of a square with an area of 144 in² is
12 in.
7.
Rational number.
8.
This is a right triangle; use the Pythagorean Theorem to find missing lengths of right triangles. Pythagorean Theorem: a² + b² = c², where c is the hypotenuse of the triangle.
Plug in your leg lengths:
a² + b² = c²
8² + x² = 21²
64 + x² = 441
x² = 377
x = 19.4
Answer:
<AEB = obtuse angle
<AED = straight angle
<BEA = obtuse angle
<BEC = straight angle
<CDE = not angle
<CEA = acute angle
<DEA = straight angle
<DEB = acute angle
<DEC = obtuse angle
Step-by-step explanation:
Answer:
[C] 25π square inches
Step-by-step explanation:
<u><em>Given that:</em></u>
<em>the long hand of the clock is about 5 inches long.</em>
<u><em>To Find:</em></u>
<em>What is the approximate area of the clock face?</em>
<u><em>Solve:</em></u>
<em>Formula - </em><em>A =πr²</em>
<em>Note that;</em>
<em>π = 3.14 (about)</em>
<em>Radius - 5 inches</em>
<em>A =πr²</em>
<em>A = 3.14(5)²</em>
<em>A = 3.14(25)</em>
<em>A = 78.5</em>
<em>Now let see the answer choices:</em>
<em>A. 5π square inches ≈ 5(3.14) = 15.7</em>
<em>B. 10 π square inches ≈ 10(3.14) = 31.4</em>
<em>C. 25 π square inches ≈ 25(3.14) = 78.5</em>
<em>D. 100 π square inches ≈ 100(3.14) = 314</em>
<em />
<em>Hence, the answer is [C] 25 π square inches </em>
<em />
<u><em>Kavinsky~</em></u>
Answer:
The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.
Step-by-step explanation:
Volume of the Cylinder=400 cm³
Volume of a Cylinder=πr²h
Therefore: πr²h=400

Total Surface Area of a Cylinder=2πr²+2πrh
Cost of the materials for the Top and Bottom=0.06 cents per square centimeter
Cost of the materials for the sides=0.03 cents per square centimeter
Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)
C=0.12πr²+0.06πrh
Recall: 
Therefore:



The minimum cost occurs when the derivative of the Cost =0.






r=3.17 cm
Recall that:


h=12.67cm
The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.