Your answer will be f(x) = 5 because, if we look at the table, no matter what x value we plug into the function, we will always get 5.
H(t)=-16t²+500
0=-16t²+500
16t²=500
t²=31.25
t=5.9 seconds before the object hits the ground
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Can you please please give me more information please thank you
A^2=b^2+c^2-2bc Cos(A)
(270)^2=(255)^2+(442.85)^2-2(255)(442.85)Cos(A)
A=Cos^(-1)(270^2-255^2_(442.85)^2)/(-2*255*442.85)=33.5435
solve for angle A approximately is 33.54 degrees.
sinA/a=SinB/b
Sin33.54/270=SinB/255
B=Sin^(-1)(sin33.54/270*255)approximately is 31.45.
180-31.45-33.54=115.01 is Angle C.
