6. To which of these abrasive disks can you

Explain 5 things that could cause an incorrect mass when using the triple bean balance?

ludmilkaskok [199]

If the scale is not "zeroed". If you do not use grams (g) to lable your products. If you do not unlock the balance. [that's about all I got doll]

5 0

3 years ago

Read 2 more answers

Two technicians are discussing service information. Technician A says that online service information is only available from the

Westkost [7]

The correct one is A. Technician Only.
The distribution of service information is regulated by <span>United States Environmental Protection Agency.
According to the rules, all vehicle manufacturers are required to make their service information available for everyone online for 'reasonable prices'.
Because of this, vehicle manufacturers started discontinuing the paper format.</span>

4 0

3 years ago

A student pushes on a crate with a force of 100 Newtons directed to the right.

romanna [79]

Answer:

100N

Explanation:

Newton's third law of motion

For every action, there is an equal and opposite reaction.

Therefore 100N of force is exerted by the crate on student as a reaction to his action

6 0

3 years ago

assume the suns total energy output is 4.0 * 10^26 watts, and 1 watt is 1 joule/second. assume 4.3 * 10^-12 J is released from e

Dmitry [639]

Answer:

$9.3\cdot 10^{37}$

Explanation:

Power is defined as the energy produced (E) per unit of time (t):

$P= \frac{E}{t}$

This means that the energy produced in the Sun each second (1 s), given the power $P=4.0\cdot 10^{26}W$ , is

$E=Pt=(4.0\cdot 10^{26}W)(1s )=4.0\cdot 10^{26} J$

Each p-p chain reaction produces an amount of energy of

$E_1 = 4.3\cdot 10^{-12} J$

in order to get the total number of p-p chain reactions per second, we need to divide the total energy produced per second by the energy produced by each reaction:

$n=\frac{E}{E_1}=\frac{4.0\cdot 10^{26} J}{4.3\cdot 10^{-12} J}=9.3\cdot 10^{37}$

3 0

3 years ago

A 2.0-cm-diameter parallel-plate capacitor with a spacing of 0.50 mm is charged to 200 V. What are (a) the total energy stored i

Debora [2.8K]

Answer:

(A) Total energy will be equal to $0.044\times 10^{-5}J$

(b) Energy density will be equal to $0.0175J/m^3$

Explanation:

We have given diameter of the plate d = 2 cm = 0.02 m

So area of the plate $A=\pi r^2=3.14\times 0.02^2=0.001256m^2$

Distance between the plates d = 0.50 mm = $0.50\times 10^{-3}m$

Permitivity of free space $\epsilon _0=8.85\times 10^{-12}F/m$

Potential difference V =200 volt

Capacitance between the plate is equal to $C=\frac{\epsilon _0A}{d}=\frac{8.85\times 10^{-12}\times 0.001256}{0.50\times 10^{-3}}=0.022\times 10^{-9}F$

(a) Total energy stored in the capacitor is equal to

$E=\frac{1}{2}CV^2$

$E=\frac{1}{2}\times 0.022\times 10^{-9}\times 200^2=0.044\times 10^{-5}J$

(b) Volume will be equal to $V=Ad$ , here A is area and d is distance between plates

$V=0.001256\times 0.02=2.512\times 10^{-5}m^3$

So energy density $=\frac{Energy}{volume}=\frac{0.044\times 10^{-5}}{2.512\times 10^{-5}}=0.0175J/m^3$

7 0

3 years ago