Answer:
The process is given in the pic.
I have taken the average masses so u substitute the values and solve hope it will help :)❤
Answer: Mercury, Mars, Venus, Earth, Neptune, Uranus, Saturn, and Jupiter.
Explanation:
That's all of the planets if you need them. Hope this helps!
Correct temperature is 80°F
Answer:
T_f = 38.83°F
Explanation:
We are given;
Volume; V = 8 ft³
Initial Pressure; P_i = 100 lbf/in² = 100 × 12² lbf/ft²
Initial temperature; T_i = 80°F = 539.67 °R
Time for outlet flow; t_o = 90 s
Mass flow rate at outlet; m'_o = 0.03 lb/s
Final pressure; P_f = 30 lbf/in² = 30 × 12² lbf/ft²
Now, from ideal gas equation,
Pv = RT
Where v is initial specific volume
R is ideal gas constant = 53.33 ft.lbf/°R
Thus;
v = RT/P
v_i = 53.33 × 539.67/(100 × 12²)
v_i = 2 ft³/lb
Formula for initial mass is;
m_i = V/v_i
m_i = 8/2
m_i = 4 lb
Now change in mass is given as;
Δm = m'_o × t_o
Δm = 0.03 × 90
Δm = 2.7 lb
Now,
m_f = m_i - Δm
Thus; m_f = 4 - 2.7
m_f = 1.3 lb
Similarly in above;
v_f = V/m_f
v_f = 8/1.3
v_f = 6.154 ft³/lb
Again;
Pv = RT
Thus;
T_f = P_f•v_f/R
T_f = (30 × 12² × 6.154)/53.33
T_f = 498.5°R
Converting to °F gives;
T_f = 38.83°F
The mass of a particle is 2.2x10⁻¹⁵ kg
Consider smoke particles as an ideal gas
The translational RMS speed of the smoke particles is 2.45x10⁻³ m/s.
<em>v= √3kT/m</em>
<em>where k= 1.38x10⁻²³J/K, T is 288K, and m is the mass of the smoke particle</em>
<em>2.45x10⁻³ = √3x1.38x10⁻²³x288/m</em>
<em>m= 2.2x10⁻¹⁵ kg</em>
Therefore, the mass of a particle is 2.2x10⁻¹⁵ kg.
To learn more about the translational root mean square speed of gases, visit brainly.com/question/6853705
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Answer:
kagak ngerti soalnya lagi ngerjain tugas sekolah numpuk
