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Sedbober [7]
3 years ago
5

PLEASE HELP ME WITH THIS ONE QUESTION

Physics
1 answer:
Ipatiy [6.2K]3 years ago
4 0

k = \dfrac{ (\dfrac{h}{ \lambda}  )^{2} }{2m}

k = (6.626×10-¹⁹/590 × 10-⁹ )^{2} /2 × 1.673 × 10-²⁷

k = (1.12 × 10-³⁰)^2/3.346×10-²⁷

k = 1.25 × 10-⁶⁰ /3.346×10-²⁷

k = 0

ldk why, my answer is coming this :(

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Answer:

Explanation:36.05 km

Given

First car travels r_1=20\ km South

then turns and travels r_2=30\ km east

Suppose south as negative y axis and east as positive x axis

So, r_1=-20\hat{j}

r_2=30\hat{i}

Displacement is the shortest between initial and final point

Dispalcement=r=r_1+r_2

Displacement=-20\hat{j}+30\hat{i}

Displacement=30\hat{i}-20\hat{j}

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v = 8.0 m/s is the final velocity

Combining the two equations and substituting the values, we  find the force exerted on the ball:

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