<span> Maths delivers! Braking distance ... If the </span>car<span> is initially travelling at u</span>m<span>/s, then the stopping distance d </span>m<span> ... the </span>speed<span> of the </span>car<span> at the </span>instant<span> the </span>brakes<span> are applied. ... An object with </span>constant acceleration<span> travels the </span>same<span> distance as it would ... We </span>start<span> with the second equation of motion:.</span>
My best guess would be:
"A force equal in magnitude but opposite in direction"
However I assume that this question is multiple choice, by the way it is introduced. Therefore it would be helpful if these options were also displayed - hence take this as my best guess only.
Answer:
Part a)

Part b)

Explanation:
Part a)
Force on the object due to spring force is given as

here we know that


so we have


Part b)
Acceleration of the object is given as



Answer:
0.1308
Explanation:
To keep the rider from sliding down, then the friction force
must at least be equal to gravity force 


where μ is the coefficient, N is the normal force acted by the rotating cylinder, m is the mass of a person and g = 9.81 m/s2 is the gravitational acceleration.
According to Newton's 3rd and 2nd laws, the normal force would be equal to the centripetal force
, which is the product of centripetal acceleration
and object mass m

Therefore


The centripetal acceleration is the ratio of velocity squared and the radius of rotation

Therefore

A paper clip is a example of a thing that has a mass of one gram.