Using the following diagram, solve for x. someone please help, its urgent

The members of the PTA are ordering pizza for a meeting. They plan to order 3 cheese pizzas for every 4 pepperoni pizzas they or

kkurt [141]

Answer:

The PTA will order 6 cheese pizzas.

Step-by-step explanation:

There is a 3:4 ratio for cheese pizzas to pepperoni pizzas.

If the number of pepperoni pizzas doubles, then the number of cheese pizzas must double as well.

So, 3:4 becomes 6:8.

The PTA will order 6 cheese pizzas.

3 0

3 years ago

I cant do this pls help

KengaRu [80]

The distance is 5. Hope this helps!

4 0

3 years ago

Read 2 more answers

PLEASE HELP FAST simplify: sqrt 8 + 2 sqrt 15

Ket [755]

Answer:

2 $\sqrt{2}$ + 2 $\sqrt{15}$

Step-by-step explanation:

$\sqrt{8}$ = $\sqrt{4}$ $\sqrt{2}$ = 2 $\sqrt{2}$

7 0

3 years ago

Find the function y = f(t) passing through the point (0, 18) with the given first derivative.

monitta

Answer:

$\displaystyle y = \frac{t^2}{16} + 18$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Functions
Function Notation
Coordinates (x, y)

Calculus

Derivatives

Derivative Notation

Antiderivatives - Integrals

Integration Constant C

Integration Rule [Reverse Power Rule]: $\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C$

Integration Property [Multiplied Constant]: $\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx$

Step-by-step explanation:

Step 1: Define

Identify

Point (0, 18)

$\displaystyle \frac{dy}{dt} = \frac{1}{8} t$

Step 2: Find General Solution

Use integration

[Derivative] Rewrite: $\displaystyle dy = \frac{1}{8} t\ dt$
[Equality Property] Integrate both sides: $\displaystyle \int dy = \int {\frac{1}{8} t} \, dt$
[Left Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \int {\frac{1}{8} t} \, dt$
[Right Integral] Rewrite [Integration Property - Multiplied Constant]: $\displaystyle y = \frac{1}{8}\int {t} \, dt$
[Right Integral] Integrate [Integration Rule - Reverse Power Rule]: $\displaystyle y = \frac{1}{8}(\frac{t^2}{2}) + C$
Multiply: $\displaystyle y = \frac{t^2}{16} + C$