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brilliants [131]
3 years ago
5

Claire correctly solved the proportion x/4 = 36/16 for x using cross products to get the equation 16x = 144 and then dividing bo

th sides by 16 to get x =9 . She showed that she can use cross products to solve the proportion because she gets the same answer if the solves it as shown
what property allowed her to go from x/4= 36/16 to x/4 x = 36/16 x 4?
Mathematics
1 answer:
Anna11 [10]3 years ago
8 0

Answer:

The cross product property

Step-by-step explanation:

The cross product property also known as cross multiplication is a method in math that is most of the time used in solving problems involving ratios usually in a big X form across the equal sign between two ratios.

It is done by multiplying the numerator of the left ratio by the denominator of the right with an equal to the multiplication of the numerator of the right ratio by the denominator of the left.

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Step-by-step explanation:

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4 0
3 years ago
1/4 of Mai’s height is equal to 2/5 of Jon’s height. Find the ratio of Mai’s height to Jon’s height.
nasty-shy [4]

1/4th of Mai’s height is equal to 2/5th of Jon’s height

Let 'x' represent Mai's height and 'y' represent Jon's height.

Therefore, 1/4th of "x" should be equal to 2/5th of "y". This gives us the following equation :

(1/4)x = (2/5)y

multiply both sides by 4/y

x/y = 4*(2/5)

x/y = 8/5

x:y = 8:5

The ratio of Mai's s height to Jon's height is 8 to 5

3 0
3 years ago
The produce department of a grocery store sold 288 pounds of tomatoes. the weight represented 72% of the shipment the store rece
Zanzabum
288÷72=4 4x100=400 so there were 400 pounds of tomatoes origionally
7 0
3 years ago
A polynomial equation with rational coefficients has the roots:​
Sedbober [7]

Answer: (5 - √1) and (4 + √7)

Step-by-step explanation:

Here we have 4 roots, then this is a polynomial of 4th degree.

We can write it as

a*x⁴ + b*x³ + c*x² + d*x + e = 0

We could rewrite this as the product of two quadratic equations:

(a₁*x² + b₁*x + c₁)*(a₂*x² + b₂*x + c₂) = 0

This will be equal to zero when (a₁*x² + b₁*x + c₁) is equal to zero, and when

(a₂*x² + b₂*x + c₂) is equal to zero.

Then we need to find the roots of these two quadratic equations.

And we know that the roots of a quadratic equation like:

a₁*x² + b₁*x + c₁ are given by:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a} = \frac{-b}{2a}   +-\frac{\sqrt{b^2 - 4ac}}{2a}

Then the general form of the roots is something like:

A +-\sqrt{B}

This means that if one of the roots is:

5 + √1, we must have another root equal to 5 - √1

And if we have one root equal to 4 - √7, then we must have another root equal to 4 + √7

Then the correct options are:

(5 - √1) and (4 + √7)

5 0
3 years ago
Someone help please!
Ray Of Light [21]

Answer:

q < 56

Step-by-step explanation:

q +12 -2(q -22) > 0

q +12 -2q +44 > 0

56 -q > 0

q < 56

3 0
3 years ago
Read 2 more answers
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