Answer:
The expected value for a student to spend on lunch each day = $5.18
Step-by-step explanation:
Given the data:
Number of students______$ spent
2 students______________$10
1 student________________$8
12 students______________$6
23 students______________$5
8 students_______________$4
4 students_______________$3
Sample size, n = 50.
Let's first find the value on each amount spent with the formula:
Therefore,
For $10:
For $8:
l
For $6:
For $5:
For $4:
For $3:
To find the expected value a student spends on lunch each day, let's add all the values together.
Expected value =
$0.4 + $0.16 + 1.44 +$2.3 + $0.64 + $0.24
= $5.18
Therefore, the expected value for a student to spend on lunch each day is $5.18
solve for x.
4x−5=7+4y
Add 5 to both sides.
4x−5+5=4y+7+5
4x=4y+12
Divide both sides by 4.
4x/4=4y+12/4
x=y+3
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Have a nice day! :)
Both have D as the correct answer.
Answer:
I’m pretty sure it’s 1:3
Step-by-step explanation:
Answer:
728
Step-by-step explanation:
formula is
Tn= a+(n-1)d
where a is the first term, d is the common difference and n is the term you are looking for
<h3>T80 = 17+(80-1)*9</h3><h3>T80= 17+ (79)*9</h3><h3>T80= 17 + 711</h3><h3>T80= 728</h3>