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The image of triangle CDE after a rotation of 90º counterclockwise around the origin is graphed at the end of the answer.
<h3>What is a rotation?</h3>When a polygon undergoes a rotation, this rotation is over an angle measure, that defines the coordinate rule for each vertex of the polygon.
For triangle CDE, the vertices are given as follows:
D(-7,-1), C(-7,-7), E(-4,-8).
The rule for a rotation of 90º counterclockwise around the origin, for each vertex (x,y) of the polygon, is given by:
(x,y) -> (-y,x).
Hence, applying the rule above, the vertices of the image of triangle CDE will be given as follows:
D'(1,-7), C'(7,-7), E'(8,-4).
The triangle, with these vertices labeled, is graphed at the end of the answer.
More can be learned about rotations at brainly.com/question/28794840
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Note that 
, where 
is the area, 
is the length, and 
is the width. Substituting our values in, we have:
Multiplying by
gives:
So the width is
miles.
Multiplying by
So the width is
Answer:
The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes
Step-by-step explanation:
We have the standard deviation for the sample, but not for the population, so we use the students t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 35 - 1 = 35
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 34 degrees of freedom(y-axis) and a confidence level of ). So we have T = 2.0322
The margin of error is:
M = T*s = 2.0322*30 = 60.97
The upper end of the interval is the sample mean added to M. So it is 204 + 60.97 = 264.97
The upper boundary of the 95% confidence interval for the average unload time is 264.97 minutes