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3 years ago

Help I don’t know the answer to this question

Mathematics

1 answer:

vodka [1.7K]3 years ago

4 0

So the x intercept is where y is 0 and x is on the x axis
y intercept, same thing, where x is equal to 0 and it's on the y axis
like the x-intercept would be: (-7,0)
y-intercept: (0,2)

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yanalaym [24]

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2 years ago

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4 years ago

the width of a rectangle is 7 feet less than it's length.if the area of the rectangle is 170 square feet, then find the length a

balu736 [363]

let length = x

width is 7 feet less than length

width = x-7

area = length *width

area = x(x-7)

170=x²-7x

x²-7x-170=0

x²-17x+10x-170=0

x(x-17)+10(x-17)=0

(x-17)(x+10)=0

x=17 or x=-10

since length cannot be negative so x=17

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3 years ago

Can someone explain to me how to find the vertex form of this equation? y= -x^2 + 12x-4

AVprozaik [17]

<u>ANSWER: </u>

The vertex of given equation $y=-x^{2}+12 x-4$ is (6, 32).

<u>SOLUTION: </u>

Given, quadratic equation is $y=-x^{2}+12 x-4$

Above equation is a parabola and we need to find the vertex of that parabola. We know that, general form of the parabola is $y=a(x-h)^{2}+k$

Where, (h, k) is the vertex.

So, let us convert the given equation in parabolic equation.

$\begin{array}{l}{y=-x^{2}+12 x-4} \\ {y=-\left(x^{2}-12 x+4\right)} \\ {y=-\left(x^{2}-(2)(x)(6)+6^{2}-6^{2}+4\right)} \\ {\left.y=-\left((x-6)^{2}-36+4\right)\right)} \\ {y=-(x-6)^{2}+32}\end{array}$

Now, by comparing above equation with general form,

h = 6, k = 32 and a = -1.

Hence, the vertex of given equation is (6, 32).

5 0

3 years ago

A computer store buys a computer system at a cost of $453.00. The selling price was set at $755, but after a year the computer

Bas_tet [7]

Answer:

40percent of 755$

40/100 × 755

=302$

therefore selling proce is 302$

3 0

3 years ago