Parameterize S by the vector function

with 0 ≤ u ≤ π/2 and 0 ≤ v ≤ π/2.
Compute the outward-pointing normal vector to S :

The integral of the field over S is then



The diameter is 10:
To do this we must use the distance formula:
Distance =√(x2−x1)^2+(y2−y1)^2
So, if we substitute in our values for the origin and endpoint (origin is 1 values, endpoint is 2)
D=✓(-4-0)^2+(-3-0)^2
Simplified, this is
D=✓16+9
D=✓25
D=5
so, the distance from the center of the crcle to the endpoint is 5 (making the radius)
multiply by two, and the diameter of the circle is 10 :)
Answer:
hi dude
Step-by-step explanation:
The correct answer is B
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