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umka21 [38]
3 years ago
7

Simplify 3^8 x 3^4/ 3^2 x3^8 . Leaving your answer in index form

Mathematics
1 answer:
Olin [163]3 years ago
4 0

Answer:

ur answer is down here in the photo thing:

Step-by-step explanation:

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Doss [256]

Consider the function f(x)=\sqrt{x}. This function has:

  • the domain x\in [0,\infty);
  • the range y\in [0,\infty).

If the domain of unknown function is [a,\infty), then x\ge a or x-a\ge 0. This means that you have \sqrt{x-a} as a part of needed function.

If the range of unknown function is [b,\infty), then y\ge b. This means that you have to translate function b units up and then the expression of the function is

y=\sqrt{x-a}+b.

Answer: correct choice is B.

6 0
3 years ago
Consider the following information related to a set of quantitative sample data:
svlad2 [7]

Answer:

(a) There are outliers

(b) x and x >62

Step-by-step explanation:

Given

\sigma = 14.92

\bar x = 22.0

q_0 = -24

q_1 = 14.5

q_2 = 24.5

q_3 = 33.5

q_4 = 64

Solving (a): Check for outliers

This is calculated using:

Lower = Q_1 - (1.5 * IQR) --- lower bound of outlier

Upper = Q_3 +(1.5 * IQR) --- upper bound of outlier

Where

IQR = Q_3 - Q_1

So, we have:

IQR = 33.5 - 14.5

IQR = 19

The lower bound of outlier becomes

Lower = Q_1 - (1.5 * IQR)

Lower = 14.5 - (1.5 * 19)

Lower = 14.5 - 28.5

Lower = -14

The upper bound of outlier becomes

Upper = Q_3 +(1.5 * IQR)

Upper = 33.5 + 1.5 * 19

Upper = 33.5 + 28.5

Upper = 62

So, we have:

-14 \le x \le 62 --- the range without outlier

Given that:

q_0 = -24  --- This represents the lowest data

q_4 = 64   --- This represents the highest data

-24 and 64 are out of range of -14 \le x \le 62.

Hence, there are outliers

Solving (b): The outliers

The outliers are data less than the lower bound (i.e. less than -14) or greater than the upper bound (i.e. 62)

So, the outliers are:

x and x >62

4 0
3 years ago
Hello! Please help. <br> "Find the error &amp; explain why it is wrong."
mixas84 [53]

Answer: Step E

Step-by-step explanation:

The error is in the last step. In Step D, we see that we're supposed to subtract the second part from the first part. We also see we have the terms 2x-8 in the numerator on the right. Since we're subtracting, the expression should actually be -2x +8. 3 -2x +8 should be -2x +11 which is not the numerator in Step E so the last step is wrong.

5 0
3 years ago
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