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2 years ago

If one guppy requires 5L of water to live happily, what is the maximum number of gubbies that should be kept in his aquafrium

Mathematics

1 answer:

seraphim [82]2 years ago

8 0

What is the Aquarium size????? If it’s 5L it should be only 1 guppie

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Which transformation carries the pentagon onto its

svetoff [14.1K]

C it’s I think lol!!!!!^^*

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2 years ago

Divya starts a painting her grandpa's kitchen at 8:15 a.m. She finishes 75 minutes later

Mila [183]

Answer:

9:30 she finishes

Step-by-step explanation:

815 plus 75 is 890

there are 60 minutes in one hour

890-60 is 830

add 100 to represent another Hour

830 plus 100 is 930

9:30

therefore, it is 9:30

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2 years ago

It takes Vanessa a half hour to walk to the library. She leaves her house at 5:00. What time does she get to the library?

serg [7]

She gets to the library at 5:30. Half an hour is equal to 30 minutes, and if she leaves at 5:00, she will be there in thirty minutes.

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1 year ago

Given that cos 42° ~ 0.743, what is the sine of the complementary angle?

podryga [215]

Cos<span> 42° ~ 0.743

cos 42° = sin(90-42) = sin 58°

So sine of complementary angle also has same value as cos 42.
So sin 58 ~ 0.743
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6 0

3 years ago

What is the exact area and arc length of these sectors? Please helppp

Karolina [17]

<u>Answers with step-by-step explanation:</u>

1. Area of sector 1 = $\frac{90}{360} \times \pi \times 12^2 = 36\pi$

2. Area of sector 2 = $\frac{45}{360} \times \pi \times 19^2 = \frac{2527}{8} \pi$

3. Area of sector 3 = $\frac{270}{360} \times \pi \times 15^2 = \frac{675}{4} \pi$

4. Area of sector 4 = $\frac{270}{360} \times \pi \times 6^2 = 27 \pi$

5. Arc length of sector 1 = $\frac{90}{360} \times 2 \times \pi \times 12 = 6\pi$

6. Arc length of sector 2 = $\frac{315}{360} \times 2 \times \pi \times 19 = \frac{133}{4} \pi$

7. Arc length of sector 3 = $\frac{270}{360} \times 2 \times \pi \times 15 = \frac{45}{2}\pi$

8. Arc length of sector 4 = $\frac{270}{360} \times 2 \times \pi \times 6 = 9\pi$

4 0

2 years ago