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aivan3 [116]
3 years ago
14

If one guppy requires 5L of water to live happily, what is the maximum number of gubbies that should be kept in his aquafrium

Mathematics
1 answer:
seraphim [82]3 years ago
8 0
What is the Aquarium size????? If it’s 5L it should be only 1 guppie
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Standard form of y+2=1/2(x-4)
gogolik [260]

y + 2 =  \frac{1}{2} (x - 4) \\ 2y + 4 = x - 4 \\  - x + 2y =  - 8
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3 years ago
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Write two different congruent statements that indicate the triangles in each pair are congruent( Odd number questions only)
ryzh [129]

Answer:

Step-by-step explanation:

17) HI ≅ UH   ;   GH  ≅  TU     ; GI  ≅ TH

ΔHGI  ≅ ΔUTH                by Side Side Side congruent

∠G  ≅  ∠T   ; GI  ≅  TH  ; ∠GIH  ≅ ∠THU

ΔHGI  ≅ ΔUTH                by Angel Side Angle congruent

19) IJ ≅ KD   ;  IK ≅ KC   ; KJ ≅ CD

ΔIJK ≅ ΔKDC             by Side Side Side congruent

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7 0
3 years ago
Roger is buying a new pair of shoes for 25% off. If the original price of the shoes was $80.00, how much money is Roger saving o
wlad13 [49]
Well, we know that 25% is also 1/4 and if we multiply $80.00 by 1/4 you get $20 so the answer is $20.
3 0
3 years ago
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The base of the following pyramid is a square. If the surface area of the pyramid is 896 in^2, what is it's volume? Side base le
MatroZZZ [7]

Answer: 457.3

Step-by-step explanation:

V=\frac{lwh}{3}

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7 0
3 years ago
Find two positive numbers whose product is 64 and whose sum is a minimum. (If both values are the same number, enter it into bot
DedPeter [7]

Answer:

X = 8, y = 8

Step-by-step explanation:

This question is an optimization problem. Two equations are going to be needed here

n = x+y

P = xy

Such that 64 = xy

When we divide through by x we get:

y = 64/x

So that n becomes:

n = x + 64/x

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We take derivative

n' = 1-64x^-2

When n' = 0 then a min|max occurs

0 = 1-64x^-2

Such that:

64/x² = 1

Divide through by x²

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Remember y = 64/x

So,

Y = 64/8

Y = 8.

X = 8, y = 8

Thank you!

3 0
3 years ago
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