<span>Based on the problems I have recently done on FLVs with this though, is that if you connect the center of the arcs to the top intersection point, if the angle degrees, and opposite arcs are the same then it is an equilateral triangle.</span>
Tanα=height/shadow
α=arctan(height/shadow)
α=arctan(292/131)°
α≈65.84° (to nearest hundredth of a degree)
Idk but you can prolly search that shi up