Maximum because it contains quartile one 3 and the media
Answer:
Problem 1) frequency: 160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)
Problem 2) Runner B has the smallest period
Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.
Step-by-step explanation:
The frequency of the football player is 160 heartbeats per minute.
The period is (using the equation you showed above):

second problem:
Runner A does 200 loops in 60 minutes so his frequency is:
loops per minute
then the period is: 0.3 minutes (does one loop in 0.3 minutes)
the other runner does 200 loops in 65 minutes, so his frequency is:
loops per minute
then the period is:

Therefore runner B has the smaller period
To convert fractions to decimals, divide the denominator into the numerator
3/9= .333333
123/999=.123123
hope this helps
After 1 sec it would be 65 m/s
after 2 sec it would be 55 m/s
after 3 sec it would be 40 m/s
after 4 sec it would be 20 m/s
and so on. The equation for this is
S = 70 - (-5(t)) where s=speed and t=time passed
Answer:
11 1/4 or 45/5
Step-by-step explanation:
just multiply 5 * 2 1/4
And thats ur answer