The combustion reaction is as expressed,
CxHy + O2 --> CO2 + H2O
The mass fraction of carbon in CO2 is 3/11. Hence,
mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.
Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g.
moles of C = 0.86 g C / 12 g = 0.0713
moles of H = 0.14 g H / 1 g = 0.14
The empirical formula for the hydrocarbon is therefore, CH₂.
Answer:
c solvents dissolve chemicals with the same polarity ( ex. both are polar)
Explanation:
Like dissolves like is one of the central rule that guides the solubility of one substance in another.
- It fully suggests substance having the same nature as in polarity-wise will dissolve one another.
- For example, water is a polar liquid, it will dissolve table salt because it i also polar.
- Water cannot dissolve oil because oil is non-polar.
Answer:
HCO₂
Explanation:
From the information given:
The mass of the elements are:
Carbon C = 26.7 g; Hydrogen H = 2.24 g Oxygen O = 71.1 g
To determine the empirical formula;
First thing is to find the numbers of moles of each atom.
For Carbon:
For Hydrogen:
For Oxygen:
Now; we use the smallest no of moles to divide the respective moles from above.
For carbon:
For Hydrogen:
For Oxygen:
Thus, the empirical formula is HCO₂
It is 50. This is because heat goes from higher temperatures to lower and nothing else in the options is lower.
