The hydrogen molecules combine with the oxygen molecules, 2 hydrogen molecules, and 1 oxygen molecules is the amount needed to make one water atom or molecule, whatever you want to call it.

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The sum of the number of protons and neutrons in the nucleus of an atom is called the

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Electron number
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Write a half-reaction for the oxidation of the manganese in MnCO3(s) to MnO2(s) in neutral groundwater where the carbonate-conta

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Answer:

The half-reaction for the oxidation of the manganese in $MnCO_3(s)$ to $MnO_2(s)$ .:

$MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}+3H^+$

Explanation:

$MnCO_3+H_2O\rightarrow MnO_2(s)+HCO_3^{-}$

Let us say the medium in which reaction is taking place is an acidic medium. And balancing in an acidic mediums done as;

Step 1: Balance all the atom beside oxygen and hydrogen atom;

$MnCO_3+H_2O\rightarrow MnO_2(s)+HCO_3^{-}$

Manganese and carbon are balanced.

Step 2: Balance oxygen atom adding water on the required side:

$MnCO_3+H_2O+H_2O\rightarrow MnO_2(s)+HCO_3^{-}$

$MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}$

Step 3: Now balance hydrogen atom by adding hydrogen ion on the required side:

$MnCO_3+2H_2O\rightarrow MnO_2(s)+HCO_3^{-}+3H^+$

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