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3 years ago

Which ion has a smaller size,1)N---,O--,F-and Ne 2) Cl-,Br- and I ?Why Help me to solve it!

Chemistry

2 answers:

Vlada [557]3 years ago

8 0

Explanation:

Ne have smaller size because Ne have no negative charge compare to N, O and F which negative charge depends on size of an atom, Therefore more the negative charge , more will be the size of atom.
Cl- have smaller size because as we go down the group, Size of the atom increase as Cl<Br<I irrespective to the atomic charge

sineoko [7]3 years ago

3 0

Answer:

nitrogen because it has less number of protons and electrons, thus a samller atomic mass

Explanation:

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How many moles are in 1.93x1023 particles of Na3PO4?

Tresset [83]

Answer:

<h3>The answer is 0.32 moles</h3>

Explanation:

To find the number of moles given the number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

N = 1.93 × 10²³ particles

We have

$n = \frac{1.93 \times {10}^{23} }{6.02 \times {10}^{23 } } \\ = 0.320598006...$

We have the final answer as

<h3>0.32 moles</h3>

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3 years ago

Acids are defined as proton donors since they release hydrogen ions. <br> a. True <br> b. False

Vladimir [108]

This is true they are defined as protons

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3 years ago

If 45.0 mL of ethanol (density =0.789g/mol) initially at 6.0°C mix with 45.0 mL of water (density =1.0 g/mol) initially at 28.0°

Likurg_2 [28]

The final temperature of the mixture : 21.1° C

<h3>Further explanation </h3>

The law of conservation of energy can be applied to heat changes, i.e. the heat received / absorbed is the same as the heat released

Q in(gained) = Q out(lost)

Heat can be calculated using the formula:

Q = mc∆T

Q = heat, J

m = mass, g

c = specific heat, joules / g ° C

∆T = temperature difference, ° C / K

Q ethanol=Q water

mass ethanol=

$\tt mass=\rho\times V\\\\mass=0.789\times 45=35.505~g$

mass water =

$\tt mass=1~g/ml\times 45~ml=45~g$

then the heat transfer :

$\tt 35.505\times 2.42~J/g^oC\times (t-6)=45\times 4.18~J/g^oC\times (28-t)\\\\85.922t-515.533=5266.8-188.1t\\\\274.022t=5782.33\rightarrow t=21.1^oC$

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3 years ago