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True [87]
3 years ago
15

Select all statements that show correct reasoning for finding 15 divided 2/9​

Mathematics
1 answer:
sergejj [24]3 years ago
7 0

Answer:

B and D

Step-by-step explanation:

If you are dividing by 2/9, that means you are multiplying by 9/2.

This can be split into multiplying by 9 and then dividing by 2, or multiplying by 9 and multiplying by 1/2.

Therefore, B and D work

You might be interested in
What property is -3(m+8)=-3m-24
Damm [24]

Answer:

All real numbers are solutions.

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−3(m+8)=−3m−24

(−3)(m)+(−3)(8)=−3m+−24(Distribute)

−3m+−24=−3m+−24

−3m−24=−3m−24

Step 2: Add 3m to both sides.

−3m−24+3m=−3m−24+3m

−24=−24

Step 3: Add 24 to both sides.

−24+24=−24+24

0=0

Answer:

All real numbers are solutions.

8 0
3 years ago
How many different 6- player starting squads can be formed from a volleyball team of 11 players?
aivan3 [116]
You have to calculate how many combinations of 6 people can be chosen from 11.   The formula for this is:
n! / [r! * (n-r)!]
combinations = 11! / [6! * 5!] =
11 * 10 * 9 * 8 * 7 /  5 * 4 * 3 * 2 *1 =
11 * 3 * 2 * 7 =
462 Combinations

Source:
http://www.1728.org/combinat.htm


7 0
3 years ago
A tank initially contains 60 gallons of brine, with 30 pounds of salt in solution. Pure water runs into the tank at 3 gallons pe
adoni [48]

Answer:

the amount of time until 23 pounds of salt remain in the tank is 0.088 minutes.

Step-by-step explanation:

The variation of the concentration of salt can be expressed as:

\frac{dC}{dt}=Ci*Qi-Co*Qo

being

C1: the concentration of salt in the inflow

Qi: the flow entering the tank

C2: the concentration leaving the tank (the same concentration that is in every part of the tank at that moment)

Qo: the flow going out of the tank.

With no salt in the inflow (C1=0), the equation can be reduced to

\frac{dC}{dt}=-Co*Qo

Rearranging the equation, it becomes

\frac{dC}{C}=-Qo*dt

Integrating both sides

\int\frac{dC}{C}=\int-Qo*dt\\ln(\abs{C})+x1=-Qo*t+x2\\ln(\abs{C})=-Qo*t+x\\C=exp^{-Qo*t+x}

It is known that the concentration at t=0 is 30 pounds in 60 gallons, so C(0) is 0.5 pounds/gallon.

C(0)=exp^{-Qo*0+x}=0.5\\exp^{x} =0.5\\x=ln(0.5)=-0.693\\

The final equation for the concentration of salt at any given time is

C=exp^{-3*t-0.693}

To answer how long it will be until there are 23 pounds of salt in the tank, we can use the last equation:

C=exp^{-3*t-0.693}\\(23/60)=exp^{-3*t-0.693}\\ln(23/60)=-3*t-0.693\\t=-\frac{ln(23/60)+0.693}{3}=-\frac{-0.959+0.693}{3}=  -\frac{-0.266}{3}=0.088

5 0
3 years ago
First answer get best marks ​
Karo-lina-s [1.5K]

Answer:

The three expressions are the first option, the third option, and the forth option

Step-by-step explanation:

I don't really know how to explain my math lol but I solved 5(1/3x+7)-3(1/2x-), and got x, and plugged in x to the equation. I got my answer, and plugged in x to the rest of the equations and the first one, third one, and fourth ones were the ones that had equal answers. You may want to check my math though because i am not the best but that is what I got.

8 0
3 years ago
Help please!!!!!!!!!!​
maksim [4K]

Answer:

110 degrees

Step-by-step explanation:

the angles stay the same even if the size changes!

3 0
3 years ago
Read 2 more answers
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