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vova2212 [387]
3 years ago
15

How many orders pair solutions does the system of equations have? -4+3y=12 x+y=2

Mathematics
1 answer:
Wewaii [24]3 years ago
3 0

Answer:

B. 1

- 4x + 3y = 12 -  -  - (a) \\ x + y = 2 -  -  - (b) \\  (a) - 3 \times (b) :  \\  - 7x + 0y = 6 \\  { \boxed{x =   - \frac{6}{7} }} \\  -  \frac{6}{7}  + y = 2 \\ { \boxed{y =  \frac{20}{7} }}

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Which is an ordered pair on the line 2.5,14 2.25,12 1.25,5 1.5,9
Savatey [412]
I would think that all but one point would be on the line.  One way to approach this problem is to find the equation of the line based upon any two points chosen at random, and then determine whether or not the other points satisfy this equation.  Next time, would you please enclose the coordinates of each point inside parentheses:  (2.5,14), (2.25,12), and so on, to avoid confusion.
                                                               14-12
slope of line thru 1st 2 points is   m = ----------------  =  2/0.25 = 8
                                                              2.50-2.25

What is the eqn of the line:     y = mx + b becomes

                                               14 = (8)(2.5) + b; find b:

14-20 = b = -6.  Then,   y = 8x - 6.

Now determine whether (12,1.25) lies on this line.  

Is 1.25 = 8(12) - 6?  Is 1.25 = 90?  No.  So, unless I've made arithmetic mistakes, (1.25, 5) does not lie on the line thru (2.5,14) and (2.25,12).

Why not work this problem out yourself using my approach as a guide? 



5 0
3 years ago
from his house Mike rides his bike 2 miles west and 10 miles north to the gym how much shorter is it to the gym if he rode in a
Dmitry [639]
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4 0
3 years ago
The radius of the circle whose equation is (x-3)^2 + (y+1)^2 = 16 is
Firdavs [7]

Answer:

4

Step-by-step explanation:

The general equation of a circle with center (a, b) and radius r is given by the equation;

(x-a)^{2}+(y-b)^{2}=r^{2}

The constant in the right hand side of the equation is simply the square of the radius;

We have been given the following equation;

(x-3)^2 + (y+1)^2 = 16

Comparing this with the general equation above;

r^{2}=16\\\\r=\sqrt{16}=4

4 0
3 years ago
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