Answer:
Hello!
After reading the question you have provided I have come up with the correct numerical expression:
4x5-1
Step-by-step explanation:
To come up with this solution you need to keep in mind some of the terminoloy being used.
The word "subtract" comes from the action of subtraction
The word "product" comes from the action of multiplication
Thus, using those terminologies correctly, you can then deduce that when the question says "the product of 4 and 5" means "multiplying 4 and 5 together".
So you get the first part being 4x5
Then, you add in the last part of "subract 1" from the "product of 4 and 5":
4x5-1
<em>Remember to keep in mind the rule of "PEMDAS"</em>
You always need to keep the multiplication portion of the equation in front of any subtraction, or addition in any given equation.
A. 2(-2) - 3
-4 - 3
-7
b. 2(7) - 3
14 - 3
11
2(-4) - 3
-8 - 3
- 11
Answer:
The shortest sides is 12.5.
Step-by-step explanation:
5 + 8 + 11 = 24
60 / 24 = 2.5
So 2.5 * 5 = 12.5

now, for a rational expression, the domain, or "values that x can safely take", applies to the denominator NOT becoming 0, because if the denominator is 0, then the rational turns to
undefined.
now, what value of "x" makes this denominator turn to 0, let's check by setting it to 0 then.
![\bf 2-x^{12}=0\implies 2=x^{12}\implies \pm\sqrt[12]{2}=x\\\\ -------------------------------\\\\ \cfrac{x^2-9}{2-x^{12}}\qquad \boxed{x=\pm \sqrt[12]{2}}\qquad \cfrac{x^2-9}{2-(\pm\sqrt[12]{2})^{12}}\implies \cfrac{x^2-9}{2-\boxed{2}}\implies \stackrel{und efined}{\cfrac{x^2-9}{0}}](https://tex.z-dn.net/?f=%5Cbf%202-x%5E%7B12%7D%3D0%5Cimplies%202%3Dx%5E%7B12%7D%5Cimplies%20%5Cpm%5Csqrt%5B12%5D%7B2%7D%3Dx%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%5Ccfrac%7Bx%5E2-9%7D%7B2-x%5E%7B12%7D%7D%5Cqquad%20%5Cboxed%7Bx%3D%5Cpm%20%5Csqrt%5B12%5D%7B2%7D%7D%5Cqquad%20%5Ccfrac%7Bx%5E2-9%7D%7B2-%28%5Cpm%5Csqrt%5B12%5D%7B2%7D%29%5E%7B12%7D%7D%5Cimplies%20%5Ccfrac%7Bx%5E2-9%7D%7B2-%5Cboxed%7B2%7D%7D%5Cimplies%20%5Cstackrel%7Bund%20efined%7D%7B%5Ccfrac%7Bx%5E2-9%7D%7B0%7D%7D)
so, the domain is all real numbers EXCEPT that one.