We have been given that a silo is in the shape of a cone. The silo is 8 meters tall and it's base has a diameter of 3 meters. Soybeans cost $414 per cubic meter. We are asked to find the total cost to fill the silo with soybeans.

First of all, we will find the volume of silo using volume of cone formula.

$\text{Volume of cone}=\frac{1}{3}\pi r^2 h$ , where,

r = radius

h = Height

We know that radius is half the diameter, so radius of silo would be $r=\frac{3}{2}=1.5$ .

$\text{Volume of cone}=\frac{1}{3}\pi (1.5\text{ m})^2 (8)\text{ m}$

$\text{Volume of cone}=\frac{1}{3}\pi\times 2.25\text{ m}^2 (8)\text{ m}$

$\text{Volume of cone}=\pi\times 0.75\text{ m}^2 (8)\text{ m}$

$\text{Volume of cone}=\pi\times 6\text{ m}^3$

$\text{Volume of cone}=18.8495559\text{ m}^3$

Now we will multiply total volume by $414 to find total cost.\

$\text{Total cost of soybeans}=\$414 \times 18.8495559$

$\text{Total cost of soybeans}=\$7803.7161426$

$\text{Total cost of soybeans}\approx \$7803.72$

Therefore, it will cost $7803.72 to fill the silo with soybeans.

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2 years ago